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原帖由 yese 于 2011-1-10 21:21 发表 $ l+ h- E) ]* I0 r, h" i z3 }
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
8 T7 C5 ~9 y6 u8 b4 q+ X' j Xcorners are connected, creating a cross within each box. Because there are fifty-two weeks
: a, J" G/ j1 ]0 B& }/ Hin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price6 [7 K9 ~, v) i2 I) Z$ Z5 \) J4 y
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional% A+ H: `! f1 Q6 |, P- E. r" @( o
divisions can be used and the angles within the original square of fifty-two still retained if% V9 c% T a- a7 H
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
- h8 p& i. ]' [. M0 Sagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still
* Z$ f9 Z, g6 R1 k$ _produce the same angled lines across the chart. When the internal corners are connected,
( f, p- Z7 H8 T1 pthe grid produces both positive and negative true geometric angles of 45º. Therefore, a
9 @: H' w0 b5 [) m+ ?' Zsimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
0 F! T" n$ t! J% F+ d$ i* Gboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by5 E8 f; }7 c8 M/ j- l8 A) K: q3 `
the Gann boxes in several ways, including further subdivision of the square by thirds or5 G) ]" C: q+ f' j
eighths. However, for this discussion we will not venture down that road.
& e2 a3 Q0 Z* [/ K o0 }
, P2 j) J9 @% ?2 bem40.gif" border="0" smilieid="203" alt="委屈" /> |
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