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谁翻译一下,谢谢哦

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1#
发表于 2011-1-10 21:21:29 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
# @- N3 n4 v; O( T1 ncorners are connected, creating a cross within each box. Because there are fifty-two weeks) J2 W/ p" j4 I9 a9 R, h
in a year, the weekly chart is using the square of fifty-two. But if you look closely at the price) H+ h4 N% m9 Q# K$ ^4 ]) r
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional) d( \9 m; @# j- X
divisions can be used and the angles within the original square of fifty-two still retained if' r& R0 ?9 u6 M
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52  j" B' X# D2 i9 j
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still1 ?9 v" S) v* ?4 W! ^6 k
produce the same angled lines across the chart. When the internal corners are connected,
7 Z, C4 l1 ^7 Fthe grid produces both positive and negative true geometric angles of 45º. Therefore, a
3 e- `, m% X9 i% n6 Zsimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the5 p3 t+ V6 H5 M: ]0 y+ b/ u
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by. p; Z* k' R  d+ Y& X& X
the Gann boxes in several ways, including further subdivision of the square by thirds or
1 \% l, \3 E& Z+ E  Peighths. However, for this discussion we will not venture down that road.
2#
发表于 2011-1-10 21:40:36 | 只看该作者
原帖由 yese 于 2011-1-10 21:21 发表 $ l+ h- E) ]* I0 r, h" i  z3 }
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
8 T7 C5 ~9 y6 u8 b4 q+ X' j  Xcorners are connected, creating a cross within each box. Because there are fifty-two weeks
: a, J" G/ j1 ]0 B& }/ Hin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price6 [7 K9 ~, v) i2 I) Z$ Z5 \) J4 y
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional% A+ H: `! f1 Q6 |, P- E. r" @( o
divisions can be used and the angles within the original square of fifty-two still retained if% V9 c% T  a- a7 H
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
- h8 p& i. ]' [. M0 Sagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still
* Z$ f9 Z, g6 R1 k$ _produce the same angled lines across the chart. When the internal corners are connected,
( f, p- Z7 H8 T1 pthe grid produces both positive and negative true geometric angles of 45º. Therefore, a
9 @: H' w0 b5 [) m+ ?' Zsimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
0 F! T" n$ t! J% F+ d$ i* Gboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by5 E8 f; }7 c8 M/ j- l8 A) K: q3 `
the Gann boxes in several ways, including further subdivision of the square by thirds or5 G) ]" C: q+ f' j
eighths. However, for this discussion we will not venture down that road.

& e2 a3 Q0 Z* [/ K  o0 }
, P2 j) J9 @% ?2 bem40.gif" border="0" smilieid="203" alt="委屈" />

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3#
发表于 2011-1-11 10:11:55 | 只看该作者
  但有一种方法来解决这个问题。图5.12显示一个系列的盒子6 h9 @' b* x/ Y1 Q  V/ H" P
  角落是相连的,创建一个交叉在每个箱子。因为有52周5 U* U) M; {5 ?8 @; p
  一年内,周表是使用广场的名。但是如果你审视其价格7 q, D. e* ^7 g6 A3 V: C
  规模,但可以肯定的是,一个盒子不包括价格范围52美元。倍数或比例
; q6 Z; x5 k- M6 d3 m: Q  部门能被使用并盎格鲁在原广场仍保有52例0 }! {5 k" |" D: t
  只有一个箱子里展示映射f

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