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原帖由 yese 于 2011-1-10 21:21 发表 ![]()
1 H$ Z/ e! o/ K+ E xBut there is a way to solve the problem. Figure 5.12 shows a series of boxes whose9 Y& X! |. _+ e# T9 B& l, H
corners are connected, creating a cross within each box. Because there are fifty-two weeks
% g0 @% ]2 w7 J1 @0 T9 N: ?: iin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price+ L: U. a: D7 t2 m& B, ~0 a9 f/ G
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional! t) l: H6 J9 m. _2 p8 { ]8 }
divisions can be used and the angles within the original square of fifty-two still retained if* [8 R, V' n+ ^; I" b
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52- i1 u) U3 @/ E6 c) D
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still
" [7 v' F* j1 _produce the same angled lines across the chart. When the internal corners are connected,6 n$ l' \$ v3 F) r( F' R, J7 O; o
the grid produces both positive and negative true geometric angles of 45º. Therefore, a# a! h1 k, z( v1 F" D
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
$ W# |) M7 Y1 Eboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
6 U( P: _5 G) |$ p: `& `# p1 k/ Ithe Gann boxes in several ways, including further subdivision of the square by thirds or) h; Y9 D' }4 `7 s& _
eighths. However, for this discussion we will not venture down that road. . J: _2 f! o; d0 ]3 Q% J
. N2 S8 J* _7 I+ k$ `2 h* ]
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