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谁翻译一下,谢谢哦

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1#
发表于 2011-1-10 21:21:29 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose# d$ B& f: q: N9 V0 n* {3 _! @3 i6 t
corners are connected, creating a cross within each box. Because there are fifty-two weeks
1 E/ g6 f, |# d, Ain a year, the weekly chart is using the square of fifty-two. But if you look closely at the price+ l. \( _0 D# T' M, Y$ B
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional7 i1 |7 ~* _9 m+ _' |: L
divisions can be used and the angles within the original square of fifty-two still retained if7 w9 O# ?/ n) i7 p) ~; Q1 y& x
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
) m2 @0 z2 o" nagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still4 t! q2 u9 }% a3 K- t
produce the same angled lines across the chart. When the internal corners are connected,
- L' V% e$ i  f; _8 wthe grid produces both positive and negative true geometric angles of 45º. Therefore, a6 w: G5 {4 i2 `- F
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the; O% N  G: w$ G; V% M! n
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
+ D- h4 o' {( _3 a# ~5 A( nthe Gann boxes in several ways, including further subdivision of the square by thirds or/ D' T# e: }  T1 ~8 \
eighths. However, for this discussion we will not venture down that road.
2#
发表于 2011-1-10 21:40:36 | 只看该作者
原帖由 yese 于 2011-1-10 21:21 发表
/ D/ i6 D. K, Z3 G) E/ p2 WBut there is a way to solve the problem. Figure 5.12 shows a series of boxes whose% _2 S6 h- F5 v: k6 q" N7 C# t& |7 K
corners are connected, creating a cross within each box. Because there are fifty-two weeks3 ?" X, I+ x, ~( v# f' o/ m
in a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
6 s/ |0 ^: b/ {6 \scale, it is clear that one box does not cover a price range of $52. Multiples or proportional
8 Z0 M$ b  U0 |5 c& odivisions can be used and the angles within the original square of fifty-two still retained if! K& O: x+ @8 T0 S
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
' S$ o. g0 r! ?  q$ M4 V/ S7 U- ~( u6 fagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still. [) H2 G  m% L; x2 T
produce the same angled lines across the chart. When the internal corners are connected," l  w6 S: R/ b( ~; i
the grid produces both positive and negative true geometric angles of 45º. Therefore, a
+ G: V% k4 U8 N% xsimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
/ ^4 e" U' L' p2 [. [: yboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by0 i% g; }; c1 @; L
the Gann boxes in several ways, including further subdivision of the square by thirds or% O2 }4 y+ P/ k8 ?3 p- b
eighths. However, for this discussion we will not venture down that road.
* a0 m# ?6 J( I- I
% s* i3 k4 G  Y
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3#
发表于 2011-1-11 10:11:55 | 只看该作者
  但有一种方法来解决这个问题。图5.12显示一个系列的盒子' A2 Z6 ^  L3 q% Z) u7 \
  角落是相连的,创建一个交叉在每个箱子。因为有52周
- A. o) ]/ L# m  一年内,周表是使用广场的名。但是如果你审视其价格
7 [5 I/ H- A, ]* H9 n! C  规模,但可以肯定的是,一个盒子不包括价格范围52美元。倍数或比例2 G9 d3 N+ t8 u& Q( x/ Y4 O2 p
  部门能被使用并盎格鲁在原广场仍保有52例  w  Y0 I6 a' w/ g
  只有一个箱子里展示映射f

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