|
|
原帖由 yese 于 2011-1-10 21:21 发表 ![]()
/ D/ i6 D. K, Z3 G) E/ p2 WBut there is a way to solve the problem. Figure 5.12 shows a series of boxes whose% _2 S6 h- F5 v: k6 q" N7 C# t& |7 K
corners are connected, creating a cross within each box. Because there are fifty-two weeks3 ?" X, I+ x, ~( v# f' o/ m
in a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
6 s/ |0 ^: b/ {6 \scale, it is clear that one box does not cover a price range of $52. Multiples or proportional
8 Z0 M$ b U0 |5 c& odivisions can be used and the angles within the original square of fifty-two still retained if! K& O: x+ @8 T0 S
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
' S$ o. g0 r! ? q$ M4 V/ S7 U- ~( u6 fagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still. [) H2 G m% L; x2 T
produce the same angled lines across the chart. When the internal corners are connected," l w6 S: R/ b( ~; i
the grid produces both positive and negative true geometric angles of 45º. Therefore, a
+ G: V% k4 U8 N% xsimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
/ ^4 e" U' L' p2 [. [: yboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by0 i% g; }; c1 @; L
the Gann boxes in several ways, including further subdivision of the square by thirds or% O2 }4 y+ P/ k8 ?3 p- b
eighths. However, for this discussion we will not venture down that road. * a0 m# ?6 J( I- I
% s* i3 k4 G Y
em40.gif" border="0" smilieid="203" alt="委屈" /> |
评分
-
1
查看全部评分
-
|