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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
% L7 t2 j0 s& G0 k4 M, v9方图计算公式
6 Y1 y4 }7 \$ H' d7 d在下面几个角度线上的:$ D" W% S0 D$ S7 d+ n
0 degrees: (2n + 5/4)squared
/ m1 ~! H% I8 z3 W45 degrees: (2n + 6/4)squared% G7 Y3 C# H. U8 h v' c
90 degrees: (2n + 7/4)squared' _! f# d9 [, J" n, L
135 degrees: (2n) squared9 P: N6 u9 e7 I9 s/ }
180 degrees: (2n + 1/4)squared
; {; u( f3 N$ ~7 l k225 d ...
1 V, }8 l R! e# [; x& E1 x& Q/ K8 U# U
0 q% L: y6 A4 h* F是这个吗?4 J" I, I% U+ L- P
: Y4 a% E0 b* E% J @2 I" K
0 O' i: }5 F0 a/ |Square of Nine Essentials
$ G9 u4 \7 y- i( F5 G, d% V- w8 B6 jDaniel Ferrera, 2002
+ n V, m2 }6 o/ C' _. K3 G* ZIn my experience with working with this method, price & must balance on a hard aspect.
1 o. A% x$ }6 p( K. mThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most! z! F* G( ?& q9 S* Y3 M+ d
important being the squares or 90-deg harmonics (0, 90, 180, 270).
; f; O* o' D8 |8 |& n- |1 _In terms of selecting a past date and price to start from, I have found that the lowest low over; {1 q0 E! o8 C( |0 X) \( r+ K
the past 365-days and the highest high over the past 365-days have the greatest influence on3 @# t i, d; [$ ?+ f% h3 e
these balance points. This technique can be used to generate the horizontal support &) F) h; U4 X2 W
resistance levels for intraday trading. This is extremely useful when you anticipate that a
' |. D; C8 c5 @& L6 A# I1 _/ kparticular day will be a trend change as the result of cycles or counts, etc.
d* V+ T9 D n. Z1 m/ c7 H5 |7 MCarl Futia's formula for this reads
2 I: @3 v2 `0 I, m=MOD 360 ((price distance or Time change)^0.5*180-225)
8 C7 @* [/ `, Z$ m5 x; RThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the" I& D1 N/ d% X+ N+ R
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
- n, ~- o: c' d- }" O7 Nof Nine chart.1 [ E) W* r, k9 e# m0 H$ k
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,- S. o, y7 N, N
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
' q; {" A4 \; _example, on the actual Square of Nine
* _, C3 u. D6 k* w16 is on the 112.50-deg angle,
% C2 I3 x- m, M) |' m! R: g36 is on the 120-deg angle,) N( F M0 g9 q1 p
64 is on the 123.75-deg angle,* ^ q3 z% c$ g: |* f) b! \9 A6 e% ]% i
100 is on the 126-deg angle and
5 c8 N% D- W) ^144 is on the 127.50-deg angle
6 h% E+ K1 W* q4 j( dand so on.
& z3 z/ j& g. i7 u0 S K4 c9 cStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle2 [$ n3 X* E* G
and the Squares of Odd numbers will Float.
4 P& J+ _7 I( Z1 {! n9 ?Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
6 s4 `! y7 n1 @4 }% S0 [6 S; `or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
9 b! D3 @1 H) {' W$ y$ \work with calculations that are based on W.D. Gann's printed Square of Nine chart, the: `+ Q3 X& |' h D
following formulas will be of great use to your research:9 }- l$ x5 U" j/ g
Ring# = Round(((SQRT(Price)-0.22 / 2),0)4 f/ W# X: P9 t
{This rounds to the nearest whole number, i.e. it eliminates the decimals}( C8 ^7 |7 T6 J" q/ |
Example: The number 390 is in Ring #10 if you crunch the above formula.3 g* m8 j7 }. a9 q
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
! b. m5 c) p/ Tother values. The Squares of Odd numbers are all on this angle.# O! P5 h( }2 S/ z, C
315-deg Angle = (Ring# * 2 +1)^24 M/ t2 Y2 k, x% }0 Z7 x
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
! T p5 j+ n7 R4 r4 n( xThe Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =: V' i/ l) _$ C0 [
371 This number is needed to calculate the angle that the 1st value of 390 is on.
2 ^' @; P7 q* O! x/ RAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg+ L L! V9 D7 a! C; E
You may have to occasionally adjust the Angle calculation because sometimes you will get a
) @* \0 d( i Bnegative value when you have a number that is approaching the 0-deg angle of the next ring.; m3 _% N+ w. a; I( ]7 B* r
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
6 Z9 T% L6 s2 N6 a- W- P! T370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -- ~$ y2 ?8 M, |5 I0 V2 M
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
- z9 Z2 a- g0 O' wwould actually be 357.75-deg.
2 s ?" `" H1 ~6 d6 i. P) NA simple formula to correct this is If Angle<0 then +360 else Angle = Angle. S& o! C4 ~8 i
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +$ K; }" H) f$ n/ K+ s4 l' j
((Ring# / 45) * Angle); F6 }9 n( ~/ B! f3 x# I7 U0 V7 C$ U
Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg! M" t' C4 L& {1 t
angle. If we want to know the value of the number that is 45-deg to this number, we would be$ z* A p; o; K# M, Y3 ?
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
7 L' q8 N B0 t' H(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =0 F$ W, A5 m. a% y7 Y, L; i; _
399.99 is 45-deg to 390.
3 S" g8 I6 l9 Z, [8 \2 S0 LKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)9 I# b& i; V' V2 W. w
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract e, ` ^7 G; Z4 R( m" Y
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-/ P) d. _1 @6 T j# x+ s0 C
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
5 H( P" B& @4 a( jwould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which# m/ P) [" H0 ^# W0 f
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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