|
|
原帖由 5575338 于 2008-7-31 17:48 发表 ![]() 9 ^8 v# y" u h- O
9方图计算公式: M) T& g, v7 C/ h. t" l/ e7 G) k
在下面几个角度线上的：" ]- Z" a" E% O8 f* [
0 degrees: (2n + 5/4)squared2 F0 Z5 Y2 @3 R# c
45 degrees: (2n + 6/4)squared
) `7 j' W0 m8 S! W% d# @4 r* v90 degrees: (2n + 7/4)squared
% D+ W& v5 }0 }) e& R `4 `135 degrees: (2n) squared
r) p% w* Q' j) A8 M180 degrees: (2n + 1/4)squared7 o# a9 J+ X# Z6 l ^7 w* |- w
225 d ...
" Q" o/ P* x: u- m4 a$ U5 q' s+ Z" g# v; a
& _1 I" i# A( b* I) w, B5 @& G, }' v
是这个吗?
1 Y. t1 M7 i, L* B3 i6 O
$ R% T; o4 ^: Y
2 c7 e l8 c' N5 h/ k# OSquare of Nine Essentials5 M0 J% K$ t: W4 `
Daniel Ferrera, 2002
2 b+ e1 c% h- Q; l7 Q% NIn my experience with working with this method, price &  must balance on a hard aspect.
- I, U7 k6 y, L& Z9 M1 B' R qThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most$ h% r _/ e. X9 k
important being the squares or 90-deg harmonics (0, 90, 180, 270).
7 q- H8 e$ |4 S' z. x8 d8 ZIn terms of selecting a past date and price to start from, I have found that the lowest low over. n' x1 z4 `# E" _' g& T
the past 365-days and the highest high over the past 365-days have the greatest influence on
+ Z& r- J% e0 ^" ]these balance points. This technique can be used to generate the horizontal support &
: q# c9 b# t5 J& t6 N: F& z, Mresistance levels for intraday trading. This is extremely useful when you anticipate that a+ Q/ V4 d5 C i5 B" l) R
particular day will be a trend change as the result of cycles or counts, etc.; ~1 o. Q' |6 L) h- V8 b1 P
Carl Futia's formula for this reads% ~. q: y: O- M/ n! V( }$ p% q
=MOD 360 ((price distance or Time change)^0.5*180-225)
+ l' W+ N) J( x; q, N' G5 jThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
- c' C/ t) U, |7 e3 H. u) q2 E& ESquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
! z4 r6 X8 n# d6 N& J* V; eof Nine chart.+ |* C1 @+ H8 e( f
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
- X5 h8 C7 x% j- Jbut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For. |) {3 U8 R) w3 ]
example, on the actual Square of Nine
& D. k$ E0 I1 v16 is on the 112.50-deg angle,
+ ~ E# ~& K1 _( y# s( t36 is on the 120-deg angle,
" w+ q# X5 E, ?4 f64 is on the 123.75-deg angle,+ o7 }1 R) N+ A+ @
100 is on the 126-deg angle and" l7 w7 W4 d* N8 V- Q
144 is on the 127.50-deg angle7 s: W" F' D& j- g2 g+ V
and so on.8 {7 \5 m8 M t) z& }0 @2 T5 `
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
( e5 |+ T% o6 \. Y* c+ fand the Squares of Odd numbers will Float.6 H- A/ x! d1 C
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw/ n) z t+ o3 O! J& h
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
- P7 l& _1 g: O2 p0 y* N6 G# b, iwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the
; m" n* P4 r4 E. p' ?" ofollowing formulas will be of great use to your research:8 t0 i+ n4 L v3 M
Ring# = Round(((SQRT(Price)-0.22 / 2),0)% x5 f/ G9 I, g% [ S: D
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
9 j6 e8 }0 b" U7 ]Example: The number 390 is in Ring #10 if you crunch the above formula.2 j+ n3 X# x6 e2 g8 x3 J0 V# c
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
8 C$ y* h" a8 P$ T; X* ^other values. The Squares of Odd numbers are all on this angle.
% p1 J' L$ {0 h- C* ^2 R315-deg Angle = (Ring# * 2 +1)^21 [4 d ]+ s0 f
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441& p$ |5 z' ~5 ?% c" l- a0 V
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
$ ^7 M+ p4 X" k6 [9 ^: F) d( g371 This number is needed to calculate the angle that the 1st value of 390 is on.
$ r* w, v) k# i6 J2 S: Y! qAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
+ x) m9 R, k" Q X- c7 `You may have to occasionally adjust the Angle calculation because sometimes you will get a, m$ c% E3 E" |6 O
negative value when you have a number that is approaching the 0-deg angle of the next ring.8 e$ p- e1 ]1 n( I( |4 B: \9 d/ x
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
' J9 t c5 O) F7 D5 x! j370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
* J6 y+ E# X2 C2 i1 o: R$ D371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this/ ~+ \ |) |. G* ]* r! T: l
would actually be 357.75-deg.$ [4 ~" b" T" `5 O
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
; g8 z1 ]; N, e L% U/ _- RTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +' y3 ~, x: i* Y6 R5 |+ \" ?4 ?+ q
((Ring# / 45) * Angle)
1 D# i0 `" W1 R: O4 }5 X, ?/ S; v9 u: kAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg* y1 ]1 T, i; Y& x9 H% U
angle. If we want to know the value of the number that is 45-deg to this number, we would be/ ?; z2 U5 N- e
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
m$ X- U( }8 n6 D; ^9 e(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
8 N2 `+ w- X! h `! U+ a! j399.99 is 45-deg to 390.
/ f% n) h. Q$ x6 XKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
) l. J' X% h9 g* w' n% fto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
+ A) d' m% \7 ]2 {90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
' U7 w! b- ~5 pdeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
4 [1 O$ f. \! o+ I& Ewould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which. X' v. q4 j4 `* h* S
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
|
|小黑屋|手机版|Archiver|【阳光飞狐】
( 网站ICP编号：京ICP备06013475号-7 )
发表于 2008-7-31 17:48:41
收藏
分享
发表于 2008-7-31 18:01:27
楼主
发表于 2008-7-31 19:22:03
