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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
' U# C7 ]1 S" t- u8 `3 @, n& M- k9方图计算公式& V) v/ y9 }# Q
在下面几个角度线上的：
3 o/ L- U5 R& R0 degrees: (2n + 5/4)squared
5 x+ s: e! }/ k+ `45 degrees: (2n + 6/4)squared
9 b3 l! e( ^$ y2 p90 degrees: (2n + 7/4)squared
* c% I: h" R$ E$ S1 c& t! J135 degrees: (2n) squared- v/ x# u) _' q) \1 V; n
180 degrees: (2n + 1/4)squared
9 w# X, U/ l a225 d ...
/ p- ]9 ?* ~9 G' H' M: V) k* P2 W/ Z* q, y% }3 W
是这个吗?7 h( j- ^% e0 u* ?' |5 d2 K
" m0 c& m5 G: D( A7 E
3 P- S5 p8 H, x( O) D: t6 oSquare of Nine Essentials3 t7 K3 V% q. }0 F. S
Daniel Ferrera, 2002
% t" e$ ?) v, R- p; B) [5 eIn my experience with working with this method, price &  must balance on a hard aspect.
+ q8 u" k5 i5 uThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
! W' p1 k8 m) k! i' r7 c, l4 @important being the squares or 90-deg harmonics (0, 90, 180, 270).7 `/ y/ E) e; e0 Y
In terms of selecting a past date and price to start from, I have found that the lowest low over
1 A3 s( J) r2 x+ M( l# pthe past 365-days and the highest high over the past 365-days have the greatest influence on
/ m! v" S$ @/ k3 zthese balance points. This technique can be used to generate the horizontal support &1 ^. s4 f1 T$ X1 I$ ?) Y. A
resistance levels for intraday trading. This is extremely useful when you anticipate that a7 ~2 W7 E: n8 f. s, G2 d( V
particular day will be a trend change as the result of cycles or counts, etc.% r! W/ ~9 i" F9 j. g
Carl Futia's formula for this reads
% @5 o3 C2 c5 e& t4 l0 t! v=MOD 360 ((price distance or Time change)^0.5*180-225)
2 A- O! e8 d8 cThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the& @4 E3 r2 s6 m9 X
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square" l" U2 m0 V0 k; B( d
of Nine chart.
5 N6 A Q2 R. T( aIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,2 k* A! C! q0 o+ f6 o! m* w) ]; O
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For8 m( F4 n1 S$ m, A9 R% x. D S
example, on the actual Square of Nine2 f. ]" J1 l: n" X! q
16 is on the 112.50-deg angle,
5 \! I2 p8 }6 q! m1 O3 s36 is on the 120-deg angle,
. Q2 v4 b" K) K64 is on the 123.75-deg angle,. W7 d2 i4 u6 p- j7 z) q
100 is on the 126-deg angle and! X" a: Q _2 b, L: G& a0 n7 b
144 is on the 127.50-deg angle
; a8 I; z5 ~6 Y0 |; Y: U; B" vand so on.6 ` Z+ H, a" y. K7 W5 G; q' e
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
! ?- `4 Y# x% ]and the Squares of Odd numbers will Float.
4 j. z/ s& V" n2 x# x# W, [2 J2 nCould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
1 @: \3 j3 _8 e& eor actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
* c6 R7 d# O3 z1 ^work with calculations that are based on W.D. Gann's printed Square of Nine chart, the& z# k- p, k& u
following formulas will be of great use to your research:
6 {* ~% i1 n: w: E% b6 T( KRing# = Round(((SQRT(Price)-0.22 / 2),0)- p f' }4 Z- I; j% i% t
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
" S. K4 l/ u7 x4 T; B3 y* a7 {0 wExample: The number 390 is in Ring #10 if you crunch the above formula.
k0 f# H k! N6 \; t315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
, q; N8 m4 e( x2 d9 u5 l9 yother values. The Squares of Odd numbers are all on this angle.9 ]# x! j* C. @* v3 @0 y, D7 G2 B/ s
315-deg Angle = (Ring# * 2 +1)^2
- I8 N" f1 f. v. M0 a; Z4 I9 WExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
2 F. L& o0 m. A! Q& {3 KThe Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 = W' A) e ?, T+ I, p
371 This number is needed to calculate the angle that the 1st value of 390 is on.
4 U. `& i/ P- L) n" j# WAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg. f9 |; m; z$ {% M" E E: ]& @7 w) Z
You may have to occasionally adjust the Angle calculation because sometimes you will get a
5 t0 ?0 w5 Q% c9 `negative value when you have a number that is approaching the 0-deg angle of the next ring.& `9 C( Y% a& I! A
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
% e c! S; E3 x: p) c370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -, R+ o; c" e4 v: ^% O, @
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this+ K q C! |9 D7 G# ~5 a
would actually be 357.75-deg.
5 Q5 U: r, ~" i% JA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.4 B! E: ~9 k0 g6 _, k6 R4 h- Y. B
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
6 J' P% S. Z( ^((Ring# / 45) * Angle)
z; h8 [1 w& `Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg
, {5 ~: c$ a3 S! o9 f, r u1 I. fangle. If we want to know the value of the number that is 45-deg to this number, we would be* V. W- d0 a7 J3 g0 j' t; o4 H+ y$ ~
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
$ P+ Y. F2 o ]6 V- i, }(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =! Z- N& B2 P9 T2 i: Q3 G
399.99 is 45-deg to 390.
4 E( x; z- K. c$ GKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
Z" j7 d* ^5 }# ~to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract# j& _& T3 G& n
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
/ `9 H; y6 o+ i6 N" b, p# X; v" C& B* Bdeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
0 I8 I" ~! p# Z# G# `3 Ywould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
4 Q+ q% B. I& C5 R. g# Ris 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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