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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
# n* A ^ a' k( i: O0 L) q1 y4 O% Z9方图计算公式" o: Q7 `1 p% c
在下面几个角度线上的：
6 i$ w6 c/ n* Y% h" x, W! A0 degrees: (2n + 5/4)squared
# N3 [5 a* ^6 }/ F8 h/ s45 degrees: (2n + 6/4)squared
% ]2 b" F! d3 @4 ^+ N* L) C: h90 degrees: (2n + 7/4)squared! f, ~ U. {( t* o1 J
135 degrees: (2n) squared
V1 C* h9 ^; U' D; h0 v k180 degrees: (2n + 1/4)squared
2 }) m4 ?0 |- C- [8 O225 d ...
9 q8 ~5 {5 y( F+ Y% t+ W
% ] q% C. S0 O& k4 w! M& c, k% m4 u
是这个吗?% ?" c0 c+ f6 @# N) T9 {
1 w/ o! P6 n. Z: ?
; x: c; z' P; r- y7 \Square of Nine Essentials5 o+ V* ~# e9 _6 @
Daniel Ferrera, 2002
' ?, A: R2 z2 k0 z1 j0 aIn my experience with working with this method, price &  must balance on a hard aspect.
& c8 ]" N5 \% K! e7 U2 ` aThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most6 R/ e+ u% p Z
important being the squares or 90-deg harmonics (0, 90, 180, 270).. U1 C% x1 o! b# e
In terms of selecting a past date and price to start from, I have found that the lowest low over
; |" ~+ N3 F+ W0 o$ N, `6 ?% b1 nthe past 365-days and the highest high over the past 365-days have the greatest influence on
% A" C# ^( J5 y! c ^these balance points. This technique can be used to generate the horizontal support &
. @- _6 t$ c! W" y" ^resistance levels for intraday trading. This is extremely useful when you anticipate that a8 d I7 f+ L( A: w z
particular day will be a trend change as the result of cycles or counts, etc.
/ k! W/ p+ h0 r5 gCarl Futia's formula for this reads) V* ?8 n j9 d9 `
=MOD 360 ((price distance or Time change)^0.5*180-225)
9 l. N$ Z7 J& G, ~This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
) k- U$ V) Q& V7 ?Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
2 T. m" n- b' Q/ F4 j0 }3 `6 m5 Hof Nine chart.
; Y$ H) ^# M1 D- d) e% |If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,4 c5 a0 B+ U7 h/ n0 J+ ^
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
' |1 z% \: G& y/ Cexample, on the actual Square of Nine
2 @' Y8 C1 x7 ]; @# z# U* N16 is on the 112.50-deg angle,' |" M+ U* e. ^+ ^: u. A
36 is on the 120-deg angle,
* I+ B# Y/ B, ?! u64 is on the 123.75-deg angle,* s" w$ J& L+ v
100 is on the 126-deg angle and6 j5 t9 z- F5 P9 _& c1 x
144 is on the 127.50-deg angle& Y( t( X2 m) s, C
and so on.' R, |3 z" {" W+ i
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle: g$ f: \0 r8 O
and the Squares of Odd numbers will Float.$ p- l. J P% d6 ?* ^
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
2 K2 u- B; ~! \7 M6 I) |3 w! a; U" q- mor actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to, ]8 q& h1 ~' \/ ]; R$ G' o
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the
% q! b _, Y; |5 ~- Y7 z! ]following formulas will be of great use to your research:* w4 s3 {" h, i7 K3 }" ^
Ring# = Round(((SQRT(Price)-0.22 / 2),0)1 d9 r0 M0 N8 m; `
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
+ ]% ^8 c) K8 s# cExample: The number 390 is in Ring #10 if you crunch the above formula.
, p2 ?! H8 t- y1 ~( t/ ~# K9 q$ c1 g315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
7 R# B; B' H$ B2 G7 G) m: S" H- bother values. The Squares of Odd numbers are all on this angle.
& [$ ~6 s F% Q, c$ `# }% g3 A315-deg Angle = (Ring# * 2 +1)^23 w+ F/ f3 H, ]/ z: e
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441+ |0 l; w5 r4 q
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
0 ?) j6 r0 R1 U+ A( a( M( J371 This number is needed to calculate the angle that the 1st value of 390 is on.& p7 `8 g3 D a6 m. v* p
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg$ Q7 N- Y4 ?* \3 A
You may have to occasionally adjust the Angle calculation because sometimes you will get a8 D0 `8 F+ `( C
negative value when you have a number that is approaching the 0-deg angle of the next ring.9 E6 X# w6 L, m, n- n
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number& S; s ^( v1 z" J0 ]3 |+ w
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -, C/ v: q% x# r3 C2 J
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
. G/ \# s7 W$ T. jwould actually be 357.75-deg.
, r* Y) j+ f$ n% |4 l. w+ {- wA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
9 j: `$ c6 ], L( d1 C5 {To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
# i% h9 U2 m4 L((Ring# / 45) * Angle)
# Z- Z8 n7 W6 Y9 eAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg/ ^6 S9 z" ~. J4 L* q9 ]# L) v
angle. If we want to know the value of the number that is 45-deg to this number, we would be) O/ v8 I* i; o# L' G Z$ c; @; v" c
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:4 i; p) m5 a$ T1 b6 K9 s; ~$ ^; e
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =) h3 `- Y) U1 ~. p5 T
399.99 is 45-deg to 390.; \0 Q- n6 R8 p' S& W$ k
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
6 g1 \1 _4 N# n! Pto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
& L& G# j. H! c+ s90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-7 T. O ], r' ]% `% G- [ H$ q2 W
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we. s' h! K% R. l7 a0 o
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which* b6 X) Y7 W' X- W9 O
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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