|
|
原帖由 5575338 于 2008-7-31 17:48 发表 1 {+ Z4 ^; \* [2 ?6 _: E3 A; z* X
9方图计算公式
5 G+ o( d/ U$ ~& O. W; r在下面几个角度线上的:$ z! k; q1 r( v+ V1 E: E& I( C
0 degrees: (2n + 5/4)squared
; J1 B. A% w* S6 `45 degrees: (2n + 6/4)squared
' @: T1 N3 s! G. }" s90 degrees: (2n + 7/4)squared/ O: i* Z% N) z% E, `% o
135 degrees: (2n) squared
: E5 i" K4 a8 V3 G- Q# f180 degrees: (2n + 1/4)squared
! i/ v% U$ s8 H6 ~$ ~5 R6 R225 d ... 0 [; v3 z- O" x" z& E8 t) Z$ D% G9 K
; I, m4 X& ~! T( I) L. F7 H
' B& ^. t: g, H1 t6 u是这个吗?
$ U. O+ x5 S6 U7 A7 z/ d9 ]: B- i- ^2 b- x4 w( G
/ z3 z1 J4 K/ w* ?
Square of Nine Essentials
. Z. J# E. u7 _" y' rDaniel Ferrera, 2002
, I3 Y3 Q4 w7 F" |+ F4 g# [1 {In my experience with working with this method, price & must balance on a hard aspect.
/ i; N4 ^+ @& D" D2 cThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
5 X, ^, g; F5 v/ ]important being the squares or 90-deg harmonics (0, 90, 180, 270).
! f" r6 `+ T# Z) M9 _4 B& ?3 HIn terms of selecting a past date and price to start from, I have found that the lowest low over
9 D2 N3 f/ w! q" n/ y4 _5 Bthe past 365-days and the highest high over the past 365-days have the greatest influence on* I8 Y6 Y* h' y+ w
these balance points. This technique can be used to generate the horizontal support &0 R7 e4 i& u3 w" }( E) S. U6 ]
resistance levels for intraday trading. This is extremely useful when you anticipate that a
( R& D8 g' [# U6 {! Nparticular day will be a trend change as the result of cycles or counts, etc.+ n3 e! U: N0 r9 k8 W
Carl Futia's formula for this reads1 G" H- Z# }7 {1 O8 e( M- {
=MOD 360 ((price distance or Time change)^0.5*180-225)
% {: u& }. q( q' S% W C& Q7 V& EThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the8 R8 Z, b( s. z5 v9 K
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square8 q0 x$ |' R, Z$ a9 k
of Nine chart.
& i; w3 x4 O; \' V7 nIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
' h9 W0 y1 F5 O9 E/ Zbut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For6 i( a% Y$ f# F3 y
example, on the actual Square of Nine5 F4 y' z/ L$ x9 \, y
16 is on the 112.50-deg angle,) {$ M# V+ v5 R6 `0 g8 w
36 is on the 120-deg angle,
% v+ M% L. S( ~) n4 N64 is on the 123.75-deg angle,0 }& M; H1 o% E8 }; J/ T
100 is on the 126-deg angle and
( s- \1 H e, l# ], A. O4 p144 is on the 127.50-deg angle
, ?0 t9 M& Z3 }$ g, @ Yand so on.
) @7 K& r4 C, ~1 u" F, V' _1 e1 aStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
o+ z- H' `- F5 y% d0 E4 fand the Squares of Odd numbers will Float.+ R% u: a- I% X
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
4 f- h/ ?3 x: for actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
7 L' S" R e, {1 V2 D( awork with calculations that are based on W.D. Gann's printed Square of Nine chart, the
& H+ [5 b! A$ Y( v U; Y4 l/ V( Cfollowing formulas will be of great use to your research:
( r% R2 _6 H) ]% lRing# = Round(((SQRT(Price)-0.22 / 2),0)
" L. O' e+ `+ F G{This rounds to the nearest whole number, i.e. it eliminates the decimals}! h2 `% F' _, s0 K/ A
Example: The number 390 is in Ring #10 if you crunch the above formula.! j0 A6 A/ H" \9 k1 L7 W" w
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all$ v, O. I* ^" }: H# M
other values. The Squares of Odd numbers are all on this angle.
7 b, S% g# G3 o8 J2 e% t315-deg Angle = (Ring# * 2 +1)^28 z- N, L- _- H3 m2 U& |- q. z% X
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441; i% {( J* b6 w0 v
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
$ ~; O* O1 W0 I* I/ q+ d' b8 a Z371 This number is needed to calculate the angle that the 1st value of 390 is on.
3 y2 z3 P9 \( G* H4 O. p @Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg7 M+ e+ q3 c; n
You may have to occasionally adjust the Angle calculation because sometimes you will get a! U* c/ _8 a; `! l3 G) |0 _2 p
negative value when you have a number that is approaching the 0-deg angle of the next ring." H E6 q6 j8 g, S& }5 q4 Z. g
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
) t4 X+ j" {3 d$ T" d" }370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -- i S D, f" ^7 X
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this* N6 v: |3 q) U# n" V" U
would actually be 357.75-deg.
/ Z! T6 c& D$ yA simple formula to correct this is If Angle<0 then +360 else Angle = Angle., C! N6 |7 V" l t
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +3 |) Q5 y7 ^: t$ O2 R! r
((Ring# / 45) * Angle)& U& ]& i. }& ^" d
Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg/ e. }, g. y& R) @; g
angle. If we want to know the value of the number that is 45-deg to this number, we would be% Y! z! D0 z( N" J" k* P
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
7 V5 F _) `" G5 A) J/ E' a& X(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =3 D) Y' [& O9 S# i- W$ e7 Z9 s
399.99 is 45-deg to 390.6 z" |: Z/ i7 \) p. L
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)% @+ D' h+ c- @- [" V
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract" n. N1 @( n- V
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-' \8 U8 \2 Y. R
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we, y4 l$ y7 p0 x) c+ _& e
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
& v2 A+ f$ S" Z e x# M% fis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
|