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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() ( m/ O( N& R( M- x5 q. K& V& [
9方图计算公式
3 x0 t4 _$ u. N3 e: g5 v8 H* A/ h在下面几个角度线上的：" l) O* V; a) E) |+ m
0 degrees: (2n + 5/4)squared! a& \7 m; @) O/ ^$ y* F+ A, Y. n
45 degrees: (2n + 6/4)squared. C. f: g1 U4 Q; M) b' d/ u. N4 \2 o0 \9 t
90 degrees: (2n + 7/4)squared
' `$ L6 }& B: g! Y6 ~- H135 degrees: (2n) squared
& D8 |/ ?* n8 L% G4 R180 degrees: (2n + 1/4)squared7 T- d. L) t: }, P
225 d ...
- W+ k- @! E. L$ s1 K* f4 K% U: j2 S3 t) M- M
是这个吗?5 ^9 @# Y# I3 a3 b0 L Z' T
E; f0 C$ r( n" a! g& F
. `; ^) V1 z7 F3 y% I8 i; l) ]Square of Nine Essentials- v, Z; V W6 u, g% w
Daniel Ferrera, 2002
3 e& c- e C9 Y* l- zIn my experience with working with this method, price &  must balance on a hard aspect., j3 Z. |2 ^& D7 y
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
/ ]; {" _5 C6 i( aimportant being the squares or 90-deg harmonics (0, 90, 180, 270).6 Q3 C; k w" E8 V7 ]2 U" g
In terms of selecting a past date and price to start from, I have found that the lowest low over
5 ~( S) L* z1 {. N. Hthe past 365-days and the highest high over the past 365-days have the greatest influence on1 L0 I2 `2 B8 T! ^! ^2 W% O
these balance points. This technique can be used to generate the horizontal support &
6 a7 T) l3 W/ L) a! z- f9 wresistance levels for intraday trading. This is extremely useful when you anticipate that a6 N3 \, y" Z7 T
particular day will be a trend change as the result of cycles or counts, etc.. A/ J+ q' x( }9 N1 w2 w1 r
Carl Futia's formula for this reads3 l# @" v# |+ G7 y6 X% }
=MOD 360 ((price distance or Time change)^0.5*180-225)( l2 ]# F* a0 \# \, S% }. ^ O
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the; K3 p' t& T1 \1 ]
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square6 d) T3 K- K$ h; S, ?, ^
of Nine chart.
2 Q& a. e" a0 S+ W! x' @If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
. V$ s& F# k: \) j" V1 ~7 V4 U6 ibut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For5 m; ?/ S! l" Z' j$ H
example, on the actual Square of Nine5 ?. I2 r4 N, `0 S
16 is on the 112.50-deg angle,
5 D: [2 r7 K& K- Z4 P0 |/ X36 is on the 120-deg angle,+ ?- E1 I) c# r( P$ ?
64 is on the 123.75-deg angle,
; k5 K5 q; W/ J7 x- Z100 is on the 126-deg angle and
9 v0 N0 ]; T9 ~% T" P/ U144 is on the 127.50-deg angle: z7 T$ L2 k5 c. i; K. ^- U0 l
and so on.
# f' i+ O8 z' n8 o2 OStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
0 h1 d( V8 o* @& d! yand the Squares of Odd numbers will Float.% ~5 v6 }. D. S) x
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw; ^3 u* L# t; ~$ ^
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to# l. t, [5 |( t* w4 L) u1 H
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the0 C; j/ [$ ^; D5 q
following formulas will be of great use to your research:/ a7 H# s7 o+ f
Ring# = Round(((SQRT(Price)-0.22 / 2),0)
: C: n7 s \2 v" L4 E/ I9 O{This rounds to the nearest whole number, i.e. it eliminates the decimals}
% h; Q9 e. [4 I0 ]0 c Y. mExample: The number 390 is in Ring #10 if you crunch the above formula.9 \& r: M5 K$ n# d- v0 U
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
" \ ~' s/ z. ]7 a( M& m( A+ Zother values. The Squares of Odd numbers are all on this angle.
; C! c* C: w) {* x5 \1 N315-deg Angle = (Ring# * 2 +1)^2: o% R; H" q: E3 R" M, u9 t0 c
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
% H$ f& {5 R4 P( {3 ~The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =5 D% B$ |2 \! Q! Q
371 This number is needed to calculate the angle that the 1st value of 390 is on.
+ L0 e7 R* K" N6 W3 `- ZAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg& o9 F6 q3 [3 I! N* x2 T
You may have to occasionally adjust the Angle calculation because sometimes you will get a
" U0 }* N2 P/ D4 Xnegative value when you have a number that is approaching the 0-deg angle of the next ring.3 q1 p8 F$ m% {1 k8 C/ D9 ~
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number$ h6 L3 m3 G+ ~- y( }5 {
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
, e- x$ z2 m- `4 ^371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
* }% [$ @* I X6 _3 \would actually be 357.75-deg.7 \1 e# H' \2 @# F; ^
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.& L1 t* r3 T7 `3 X* i) q
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
( w5 H7 G; d7 k: b. l" ^8 i((Ring# / 45) * Angle); o& U+ D( @, c/ G$ Q$ p
Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg+ i1 q( F8 w ^7 G
angle. If we want to know the value of the number that is 45-deg to this number, we would be1 O, S" U3 v, e7 \2 t% c
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:' h4 r2 r/ Y# X* z/ ]2 |
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =& O7 f% L* F/ @2 |
399.99 is 45-deg to 390.
2 F9 [8 z* @4 y" N8 ZKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)5 Z4 a) x7 P; J% o8 t4 S* h- p
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
# W5 C. a% Y/ @90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-8 b# u; b7 y* |$ ?8 K1 r
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we* ?7 w4 R' E" P1 g6 w
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
! r" ~' H/ U; K5 Y/ u% i' S+ k9 uis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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