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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() $ R5 A/ H) X. ?5 {
9方图计算公式
% |9 N1 s7 c8 i0 F) g. O在下面几个角度线上的：% e$ F% _# @; ?7 {* z0 M5 Z" }
0 degrees: (2n + 5/4)squared$ C" t8 ^4 Z' w
45 degrees: (2n + 6/4)squared1 f5 [, F, d: ~2 ?
90 degrees: (2n + 7/4)squared
8 ^6 _- ~) H8 _5 _8 X- w! U2 ?135 degrees: (2n) squared
% `2 b b# v4 F& G1 ~+ H180 degrees: (2n + 1/4)squared6 H9 T/ E# r% h9 }# c. j
225 d ...
5 { `$ ?, W! i1 t' ]/ P: A# @5 \; x
# j3 u* k ~ r$ o* a+ b2 U$ D* j: Z是这个吗?. Z: P! i; l& m7 R. c3 y
, [' G, ]. O' j1 G. [9 T6 D" b. t% R# D6 Z8 p! n, ]3 n
Square of Nine Essentials
, e& _$ a* Q ]1 D4 fDaniel Ferrera, 2002
3 g; @0 C) A! _; F; TIn my experience with working with this method, price &  must balance on a hard aspect.: Y7 v3 J+ _1 y6 \: ^2 o
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
6 l C! K$ Q l, W% Himportant being the squares or 90-deg harmonics (0, 90, 180, 270)./ m* e+ M# y: V+ { L) N7 R
In terms of selecting a past date and price to start from, I have found that the lowest low over
G3 e4 j+ V7 F6 S1 e/ Athe past 365-days and the highest high over the past 365-days have the greatest influence on( T( _' {/ y/ c1 l6 q/ @
these balance points. This technique can be used to generate the horizontal support &
, t. H$ k6 }4 b/ `+ eresistance levels for intraday trading. This is extremely useful when you anticipate that a
+ Z+ n3 E+ G( H( A/ h9 j' T6 |particular day will be a trend change as the result of cycles or counts, etc.
+ |0 q2 j; d/ J: V- y0 YCarl Futia's formula for this reads
" l1 T! c- U, i; G! @- E0 D* Z=MOD 360 ((price distance or Time change)^0.5*180-225)+ ?3 [$ L `& T% ]6 ^& ]) G
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
+ E( r" x s) ] D& _" Z% P* ?Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square1 n/ k2 y# G, x* V
of Nine chart.* @/ e' }# D. \; Y- l5 s
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,: C! f( q9 |$ H& U4 M3 C* A
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
. X y' p/ N9 vexample, on the actual Square of Nine5 }* m/ s) z8 z% I' {0 m: d7 a
16 is on the 112.50-deg angle,% W% @ Q- ]: M v: `
36 is on the 120-deg angle,
" M4 @ b% t0 q* E: s" b; `64 is on the 123.75-deg angle,
0 s' z* [1 |+ X4 D100 is on the 126-deg angle and; ?# ^# B: ?) F0 ~! q1 h7 ?
144 is on the 127.50-deg angle- B; l" H g+ |6 {/ L# L
and so on.
7 A- S: k' i4 k: w+ U4 `) vStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle. Y8 s( i C0 Z. o' q
and the Squares of Odd numbers will Float.
( P9 X! O7 w' X2 _* VCould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw2 ~4 y0 _: i4 |4 X1 B; y
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to* I. M0 F# { n0 r
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the
# Z v0 w7 E; u8 ffollowing formulas will be of great use to your research:
" N: L( ]* `' i0 N. XRing# = Round(((SQRT(Price)-0.22 / 2),0)
& {/ W9 N' F2 V0 i{This rounds to the nearest whole number, i.e. it eliminates the decimals}& t" ]! E* c% Y; h W
Example: The number 390 is in Ring #10 if you crunch the above formula.# C3 F7 }! K2 q G4 H/ F. @
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all9 A/ w, q( Q4 Q( o" i! H
other values. The Squares of Odd numbers are all on this angle.1 C0 E3 X3 o8 N5 K5 c
315-deg Angle = (Ring# * 2 +1)^20 Y5 Z4 `2 G2 J& A/ H
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441 X+ M1 S B) s% {5 |% r
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
+ i5 Y8 T/ k' |: S! I' ~371 This number is needed to calculate the angle that the 1st value of 390 is on.
* J4 B' O4 w' M, t/ `Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
; e. g+ U+ }! FYou may have to occasionally adjust the Angle calculation because sometimes you will get a- U, z0 M# \0 c! M5 q! s( F8 ^
negative value when you have a number that is approaching the 0-deg angle of the next ring.
# D. k# T" r. _ c) w! YFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number
% C& C& Z/ A8 M" i3 v2 e: ^370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
A* h0 R7 U: ~1 Y/ U9 i371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
4 d1 z6 l! y' }! O3 L8 j8 g* u; Hwould actually be 357.75-deg.) S ~0 ` p3 j+ c2 F+ j5 p
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
; n0 K6 _' T h" }! n4 nTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
, D0 G9 O ~) R& Q, p$ D; W((Ring# / 45) * Angle)
- w3 y) K5 x3 u* C- f1 @. zAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg* P% l( Q$ f/ w
angle. If we want to know the value of the number that is 45-deg to this number, we would be- _" W" ~& H }# @
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
9 S. r w( a t0 D* A4 s5 ]! N. Y(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =( d U, M# u" ^* E* Q5 }( ^+ d
399.99 is 45-deg to 390.+ L: c. A2 | y W d
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
; [; |0 x1 ~, I; Y1 J5 c4 @to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract, P8 w) }3 Q. A% }
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50- D. W' U& _- L! `) \
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
/ a4 D! e. F+ t; gwould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which& K# ?9 ^5 S4 ^5 G a
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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