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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
% G' J+ C! y; j5 o9 V( _+ X9方图计算公式
% r+ D& c) @' q7 d/ P5 V% x. M' n在下面几个角度线上的：0 S7 C# H/ ]. w8 L4 ?
0 degrees: (2n + 5/4)squared
; G8 b; S* K2 U( t& r% U* v+ K, X45 degrees: (2n + 6/4)squared- X, T6 i! ]3 y8 N8 L( J6 K0 l
90 degrees: (2n + 7/4)squared
- ^$ e6 y+ q3 D7 |' e135 degrees: (2n) squared
/ v4 q( v% B7 h+ Y4 K9 ]180 degrees: (2n + 1/4)squared
* B: l9 l w4 |, s6 Z225 d ...
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( C7 u7 Q4 b" H" O% I" i4 R
8 }5 W q" Q% U/ J+ m' Q7 Z是这个吗?- x! ]9 D& y' b* ~" s# l
' Q; \8 p3 F3 ]
9 ^4 i) ?9 l' t" Y% ESquare of Nine Essentials3 f5 R2 s* R; J* [2 Q
Daniel Ferrera, 20024 n1 D1 n; l9 Y, u B# `, M3 u
In my experience with working with this method, price &  must balance on a hard aspect.- A; V, F k4 J1 R% ~2 e3 V9 O1 u
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
) C' h8 ?4 \6 j8 H- Wimportant being the squares or 90-deg harmonics (0, 90, 180, 270).# W' O% h5 E2 m: ~ a
In terms of selecting a past date and price to start from, I have found that the lowest low over
& u5 c" C* @/ C' O! W+ D4 _& j3 Jthe past 365-days and the highest high over the past 365-days have the greatest influence on
+ n* T, K4 K/ C- }& a4 hthese balance points. This technique can be used to generate the horizontal support &
' p- d0 N& ]: r, }+ J5 T6 x0 Presistance levels for intraday trading. This is extremely useful when you anticipate that a' T* `1 D8 Z$ C( I9 T
particular day will be a trend change as the result of cycles or counts, etc.
( }, V; D) G) F0 B: ~1 wCarl Futia's formula for this reads
" r3 i7 J: T0 m* S' w=MOD 360 ((price distance or Time change)^0.5*180-225)
9 B E1 @2 m f* `4 J5 MThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
0 P+ s) ^5 o! i) K% }7 w& l tSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
+ o- c: y$ d S/ P% H# b7 oof Nine chart.
/ Z$ E6 W3 Z# \4 v2 uIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,% I- D% K0 {( v
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
' E5 `2 z _8 j' U8 p" zexample, on the actual Square of Nine
; x k# O4 a- i/ a9 s l16 is on the 112.50-deg angle,
# X! B; _7 P: ?36 is on the 120-deg angle,
1 w1 r0 N5 ^' E1 t" G64 is on the 123.75-deg angle,
" K; D6 O* t8 a( l6 U: o4 z) h100 is on the 126-deg angle and
% W! g9 i) T% V, Y5 |2 d/ u144 is on the 127.50-deg angle2 A5 {' H5 E; A/ @ F ^
and so on.8 [/ w# }' l6 ^5 B# W0 \4 k
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle, h! n2 f# J2 R" }' Q8 g
and the Squares of Odd numbers will Float.
( O1 m; x {, M. b1 ?Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw, q/ z" z" h+ x% F! M
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
- y2 K6 U$ i) B! J3 [! t {- l. Y3 Iwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the. P9 X; j: c; R O- p: ]$ j
following formulas will be of great use to your research:. z6 m; ^( E0 u! ~1 x% c
Ring# = Round(((SQRT(Price)-0.22 / 2),0)
/ j8 \5 g" g4 @0 X5 _, x) N& m{This rounds to the nearest whole number, i.e. it eliminates the decimals}
) ?# {; x; N7 x) Z# xExample: The number 390 is in Ring #10 if you crunch the above formula.1 \6 T) |% R. R/ m
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
/ a. s) u' A/ v3 b# P7 Pother values. The Squares of Odd numbers are all on this angle.
H, O8 ]$ T K6 e% {9 o1 A315-deg Angle = (Ring# * 2 +1)^2$ c1 e. @- u" r6 {( c2 s+ `
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
4 O* L" b% D% L1 @$ U/ N" EThe Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
- U4 b+ s$ w( R! Q. |371 This number is needed to calculate the angle that the 1st value of 390 is on.
- i* r: ~' S% `. Q6 F. oAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg9 e, P/ [" b2 \! c
You may have to occasionally adjust the Angle calculation because sometimes you will get a
/ l: q2 O4 n: G/ @8 g9 R9 bnegative value when you have a number that is approaching the 0-deg angle of the next ring.
+ _' R* C; c' V: q; D( _/ NFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number' J1 k2 A& w* n8 U: b' a4 b! N4 R
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -$ I: r0 u+ l6 N5 E6 q: h: D
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this2 S$ |( ?& ?( [+ [ Y+ ~
would actually be 357.75-deg.2 U! S4 j+ G1 P- h
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
1 K8 a& J3 i/ p9 M, w, QTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +/ [ N* o" ]9 Z. R' i" j
((Ring# / 45) * Angle)
& z+ `0 a" |+ |: C4 {) VAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg% q) s# _# P1 ]% F- x" }
angle. If we want to know the value of the number that is 45-deg to this number, we would be
2 v: E! j* h! {' Z' O s, Sinterested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
( `9 c0 v% U8 [- a# {(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =' q* u( p% k0 i L4 k5 q3 n
399.99 is 45-deg to 390.
' @: @7 ?6 F' y/ L! B2 p B$ tKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
1 k3 p; Y$ {% q s o" o6 vto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract* w" W7 [; P! L
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-' h/ p8 m1 R1 d; K
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we9 j& `, z" G5 h: l# u! Y) I- |
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
& ~2 E* y* v1 m4 V2 L: D# e0 Pis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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