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原帖由 yese 于 2011-1-10 21:21 发表 0 L% b+ A- P3 X A. P. p6 O5 N
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose3 r0 U/ U d8 O1 D Q
corners are connected, creating a cross within each box. Because there are fifty-two weeks
, ^# l8 v Z) P z- j4 w0 Jin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
% I- q2 B7 H6 u9 `/ S/ Bscale, it is clear that one box does not cover a price range of $52. Multiples or proportional' G4 J8 V5 S: ~ B) g- i! \4 [
divisions can be used and the angles within the original square of fifty-two still retained if
: Q3 V2 F& o$ @) J$ _! a' U5 t9 l& z+ sonly a single box were displayed mapping fifty-two weeks along the horizontal, versus $522 Z2 r) a6 S' c- [, u1 n& a& N
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still
/ A& [ e2 w- M+ g# hproduce the same angled lines across the chart. When the internal corners are connected,! |6 P7 t- I. [" ]
the grid produces both positive and negative true geometric angles of 45º. Therefore, a2 r; a5 k9 |, W: |! \& V
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the$ ~( \' Z) H( y/ l
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by( {$ l$ O! N1 S b4 u7 g& y8 Z) I# @: p
the Gann boxes in several ways, including further subdivision of the square by thirds or
1 `; q- v/ l2 B4 Xeighths. However, for this discussion we will not venture down that road. 0 x. m8 S: |& q3 M, i, G
7 `; ^* b2 t$ n& L; i4 q: c
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