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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() & f* c0 f( O$ `$ ?4 N# N
9方图计算公式. L$ r+ }# E8 |4 u' f
在下面几个角度线上的：3 C3 Y$ Q1 i3 z3 [' |# Q9 u6 g
0 degrees: (2n + 5/4)squared
) R, c# i5 _ h9 |45 degrees: (2n + 6/4)squared
/ Y O2 j( n! a @2 h0 x90 degrees: (2n + 7/4)squared( U) f! I% \. ]0 [2 w: R
135 degrees: (2n) squared4 a3 s, k( j7 V2 c
180 degrees: (2n + 1/4)squared2 n1 ~1 |2 N @8 B) \7 g
225 d ...
8 X' h7 w2 u' |1 _7 z& U
; z3 n9 U. s4 y+ e A- e8 v, x7 S7 e5 z/ P
是这个吗?
/ p2 E' `- p9 y# _' v% h3 K+ d% V$ S' K# _# \+ C
. J# P0 L# J/ i8 U- T# YSquare of Nine Essentials6 M( m `" v8 k4 g% K
Daniel Ferrera, 2002
1 i$ b8 Y2 i$ Z) iIn my experience with working with this method, price &  must balance on a hard aspect.* F! l1 K) v& P% b% r1 a
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
' z6 Y ^" O4 ^important being the squares or 90-deg harmonics (0, 90, 180, 270).+ u; n8 K* m8 C3 o+ c8 `
In terms of selecting a past date and price to start from, I have found that the lowest low over! A; @7 h6 [/ K& A8 l- H
the past 365-days and the highest high over the past 365-days have the greatest influence on
' M+ I% O7 u" B* Gthese balance points. This technique can be used to generate the horizontal support &7 N; |# d" L0 A# A
resistance levels for intraday trading. This is extremely useful when you anticipate that a/ Q: d9 [& l6 @6 }1 |: B, z' n* f/ V
particular day will be a trend change as the result of cycles or counts, etc.
! x. q$ i% c8 h7 I' [Carl Futia's formula for this reads, v% L" B* H A5 k0 N3 o2 P
=MOD 360 ((price distance or Time change)^0.5*180-225)9 M! n* K# g5 C0 {9 ~$ c0 h) I9 o
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the: r! A' o" W) t% M9 I
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
" y0 }! G/ p/ x3 M' N0 `of Nine chart.
0 r- u; s' i' q& r8 vIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,3 o( _. s8 m9 e; |0 X
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For( w* N$ Y8 G3 E& k* N
example, on the actual Square of Nine, k3 |" o, R- U$ M" z5 _* ?7 O
16 is on the 112.50-deg angle,) b. G9 W3 L' r* ]6 h
36 is on the 120-deg angle,
( |. z; t4 g. u1 n2 g! A0 T64 is on the 123.75-deg angle,
" B" l9 v6 f- P; a, ?/ P: ?100 is on the 126-deg angle and
. P3 D3 i8 k: {0 T8 N144 is on the 127.50-deg angle$ B4 W- P, P# q
and so on.# @% f. ~+ `# L; Q
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle& T& C' S# l- `3 M; c
and the Squares of Odd numbers will Float.
; `- A% k" `9 s# }+ ICould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw, i( K8 f8 [) F( M' X
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
4 T3 h- g w' s X, a( Zwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the
/ D/ q8 k' ~0 j; f1 ofollowing formulas will be of great use to your research:
6 v" }) P3 B3 n" I" E: q+ |Ring# = Round(((SQRT(Price)-0.22 / 2),0)% T, `$ l2 Z! @' L1 h
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
# Y! x1 t* E. ?/ d. G; o& T0 ~" x3 ^Example: The number 390 is in Ring #10 if you crunch the above formula.) L& V r: ~ J, D
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
- |* {; }2 j7 qother values. The Squares of Odd numbers are all on this angle.
5 a; \, h4 M; k! G5 J+ n$ q; `1 H! N# d315-deg Angle = (Ring# * 2 +1)^2
5 U- F" H/ U! {& ?Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
1 ^* F" F! w( BThe Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =/ K% H' G5 k( j9 L2 v/ |
371 This number is needed to calculate the angle that the 1st value of 390 is on.
{( U. l+ F/ Q! L5 wAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg0 w: F* |' k: K0 [! e! {
You may have to occasionally adjust the Angle calculation because sometimes you will get a1 D: W& u) |1 {% ]+ H
negative value when you have a number that is approaching the 0-deg angle of the next ring.
* Y8 S W3 I9 _# c# [2 Z @. ~For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
( n2 m! u# b* t* s5 R5 H& w370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
& T: |) p/ {5 l; z! Y' ?. |371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this/ H. K4 G6 W' |7 S
would actually be 357.75-deg.
. D% v; E# y, L+ C% Z0 O6 OA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.% a: k. ^" f* H" r; B
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +: \, K# s6 x: a- ^+ m& G3 ^6 K
((Ring# / 45) * Angle)
F6 h8 M( O$ I4 E( g" MAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg
2 L6 N+ f% b+ z7 Rangle. If we want to know the value of the number that is 45-deg to this number, we would be
/ ~. \' v; e- H1 A1 C r& q1 @' p* u# [interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:8 y1 J8 C5 T v$ g) p
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =7 }8 t, ^6 G# U7 |$ ^$ o% H# g
399.99 is 45-deg to 390., Q5 T# g# L8 S' K/ d
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
# ?% ]2 c4 z' }) x& m" ?% V& wto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
, @( a9 }! _/ D/ V* @, x90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-' d4 i# P+ T+ U/ U+ S' P9 W
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we/ y7 a( I3 d) M. o
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which6 X% n+ E3 ~: y L" E/ s1 C
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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