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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() ' ]7 h( x" \) v0 b1 }
9方图计算公式
1 s5 j, ~/ o; Q. P0 [2 G6 ~/ D) b在下面几个角度线上的：
+ y- X8 T1 ?* q& Z5 \( _* ` ]0 degrees: (2n + 5/4)squared
( O7 x- v& V) [- Z6 t$ t45 degrees: (2n + 6/4)squared4 \0 b/ B) i% e. @% F5 ^% F5 s6 ?
90 degrees: (2n + 7/4)squared2 F: l# t, m; S
135 degrees: (2n) squared* T. s" x# r( ?2 }* H
180 degrees: (2n + 1/4)squared
9 j( O+ G; o R8 J2 c/ z225 d ...
7 H3 \- r2 t* k# t- ?! B
! i, X# ?$ s( i1 a# }2 v" r是这个吗?
* `( k, @; a7 h" p* Z/ }% G, W2 S# Q- j6 K! q0 w
+ Q$ h9 g7 }' N# N: |8 j: Z6 S
Square of Nine Essentials, r. m; m2 E: J9 [# \
Daniel Ferrera, 2002
+ i- J2 @) K ]. `: ]In my experience with working with this method, price &  must balance on a hard aspect.
0 t" b. l$ k# ?4 ~0 FThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most+ G" K% O: F9 V
important being the squares or 90-deg harmonics (0, 90, 180, 270).6 j& M( X6 P3 f% k/ Y0 C
In terms of selecting a past date and price to start from, I have found that the lowest low over+ F* j+ y$ ~/ w' {" Y6 T
the past 365-days and the highest high over the past 365-days have the greatest influence on& H, s' D$ y+ q3 \7 q* |, S
these balance points. This technique can be used to generate the horizontal support &8 n) K3 m; L/ _
resistance levels for intraday trading. This is extremely useful when you anticipate that a
* x6 i7 h/ H4 r( T$ `, Jparticular day will be a trend change as the result of cycles or counts, etc." G# d9 v7 Q* }+ Z* h
Carl Futia's formula for this reads
0 V% I6 U1 V( B: {+ s) l9 e" r=MOD 360 ((price distance or Time change)^0.5*180-225): q1 J' X7 E2 [! Q1 a3 D
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the! e: [0 E% p9 i5 q) A" b) J
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
: x8 H. L) }, Q" Hof Nine chart.
9 p9 k* w. s) J3 }/ i/ IIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
5 G0 t& M9 R: ^' K( k' `5 Dbut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For! N* `4 {3 r) V9 \
example, on the actual Square of Nine
2 E- W2 s) V4 t6 E16 is on the 112.50-deg angle, o( }' x- G) ?$ B* ]
36 is on the 120-deg angle,
# L4 g& P5 n2 g$ i; y4 b64 is on the 123.75-deg angle,
: J, l/ D/ V a( H& {100 is on the 126-deg angle and7 V8 n( p5 k- D$ O8 o+ G6 [8 p8 o
144 is on the 127.50-deg angle4 T) y7 D4 z+ V3 [- c/ w0 a3 S
and so on., ^# _' c1 }6 @0 \( P
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
8 D/ ]6 J/ i+ T: iand the Squares of Odd numbers will Float.
! E$ r0 h7 y5 _ d Y9 qCould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw+ Q o' c5 y0 A7 f/ i
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to7 B6 n( O2 L: ?* |! i# S7 G% D
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the
, t4 l6 q" d$ Qfollowing formulas will be of great use to your research:
. n; e" N5 Q8 V. E: [: l. PRing# = Round(((SQRT(Price)-0.22 / 2),0)5 G0 e, W* l% O/ t
{This rounds to the nearest whole number, i.e. it eliminates the decimals}: |2 {+ B) i& @6 K6 K' m
Example: The number 390 is in Ring #10 if you crunch the above formula.
7 ^& j8 A( T E J4 R315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all% n; Q; H. V( X, J+ q4 [, o
other values. The Squares of Odd numbers are all on this angle.
, e$ e4 J: V# \8 O315-deg Angle = (Ring# * 2 +1)^2
# s! F2 v" v. h% }/ O; VExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 4419 K! t s5 s9 [3 \
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
3 e5 y o( U" v$ i# y0 d371 This number is needed to calculate the angle that the 1st value of 390 is on.4 c1 K8 b6 P( ? [8 ?7 f! W. ]$ Y
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
; i2 I3 K: b& f4 hYou may have to occasionally adjust the Angle calculation because sometimes you will get a
a, y! D2 J; [- Snegative value when you have a number that is approaching the 0-deg angle of the next ring.
* l C$ L' b& l* ]1 oFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number- X* W5 ]/ ^4 c4 q/ Z/ B: P
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
, @+ f+ x j# k& J: @7 N* J371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this8 ^8 h3 x+ q/ ^- e w
would actually be 357.75-deg.7 k, c: q6 o" X" S0 ]! A7 h
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
3 l) ?7 z0 Y& C' J2 d HTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
$ s0 X+ j& |3 r0 C1 O((Ring# / 45) * Angle)
4 [* s/ R, N9 T& {, J9 CAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg v0 x. {! m+ M4 m
angle. If we want to know the value of the number that is 45-deg to this number, we would be( \4 k0 ?; z2 s6 h
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
. z. B# u! ^% P5 g. b U. C9 X(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =& Q. k! X1 Y3 @+ J2 y Y4 O6 p
399.99 is 45-deg to 390.9 |! ?9 G$ q: [$ f: ]! a9 ~
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
) c" [- [7 r: t4 eto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
' Q3 Y+ ] r- n1 N3 c) P8 p6 {$ W90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-+ R8 t! P8 B' [
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
) J/ j% I9 T, F9 ^5 B0 q+ {would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
1 }: w7 U$ o: _% X. B: P5 x% ~3 Xis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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