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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() ; d; S4 m* K* @; W" Z# R
9方图计算公式
: v. i0 [9 J+ ~" |在下面几个角度线上的：% ]) H2 J& _# \6 f; _
0 degrees: (2n + 5/4)squared
; O% X& M5 L5 i& B. h n! y45 degrees: (2n + 6/4)squared
* Q" d1 w7 y$ p, L4 {3 \( b% x! C- W90 degrees: (2n + 7/4)squared& H7 c3 f% `( I& C! w0 {8 T
135 degrees: (2n) squared
* ]% G1 x8 \0 V( p' P$ ~$ E0 Y180 degrees: (2n + 1/4)squared8 M( g. e! l9 I$ d+ U
225 d ...
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# f! Y2 |/ }- A/ `: Z0 g' a
是这个吗?
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; r0 j" M5 O) rSquare of Nine Essentials) K$ s o1 A4 f- r2 V2 T, w
Daniel Ferrera, 2002 I! m' V, L1 v ]( Y) E
In my experience with working with this method, price &  must balance on a hard aspect.
. h# ^5 b2 U5 M5 T* Y7 y1 CThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most" w( M' ?& M+ J- f) i c4 ]% T
important being the squares or 90-deg harmonics (0, 90, 180, 270).
. v& ~6 K7 p. Z `8 l1 h" oIn terms of selecting a past date and price to start from, I have found that the lowest low over
6 l' G$ H. x& z$ Othe past 365-days and the highest high over the past 365-days have the greatest influence on# K* p6 D7 C8 z) k
these balance points. This technique can be used to generate the horizontal support &- B Q1 ^' @7 X. [; R+ L- F9 d8 V3 A
resistance levels for intraday trading. This is extremely useful when you anticipate that a: U& x! r9 C* @0 o# J$ R3 Z
particular day will be a trend change as the result of cycles or counts, etc.
- u, _+ E, f4 I( Y9 } zCarl Futia's formula for this reads2 h& G* ]" o0 k% ~9 h( Z) o
=MOD 360 ((price distance or Time change)^0.5*180-225)
) ]8 ~ d L2 s, n3 AThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
4 M! r9 z! a4 Y( b+ GSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square K2 T9 i* c, d" c, a! w
of Nine chart.
3 r! Q- H# \1 Q3 v8 Y: a- s% DIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,0 y' }) }, ~3 j. e# i! k' l
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
V& Q$ Q ~* p9 yexample, on the actual Square of Nine/ f5 P: B$ R8 ^4 o' c2 m \# s
16 is on the 112.50-deg angle,
- K4 t( F: |( ~# @0 e5 @ [36 is on the 120-deg angle,
$ v# p3 {% |% g( A; B1 Y64 is on the 123.75-deg angle,
8 b) k" O# S" x. o& }' K1 ^3 `100 is on the 126-deg angle and. e" J# r7 l4 T: w( |- l
144 is on the 127.50-deg angle
# V0 }( k( }6 Q, @' h3 V7 Yand so on.
9 l! m* ]" K4 c) XStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle3 Z9 y$ @* a. B7 I# v( f! _! N8 V
and the Squares of Odd numbers will Float.+ C3 }0 T2 d! _# e- |
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
d2 K5 {) a, @% zor actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
; K& A- G* t @& Y+ Iwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the
+ X3 i; e0 T6 e9 t Ufollowing formulas will be of great use to your research: X3 y; U( b, p/ |8 S! ~, L
Ring# = Round(((SQRT(Price)-0.22 / 2),0)
8 Y$ g* V4 j6 @2 B{This rounds to the nearest whole number, i.e. it eliminates the decimals}
5 O5 K$ n2 w+ K! V+ B2 L: sExample: The number 390 is in Ring #10 if you crunch the above formula.: C* ?) o' H. s. _/ M8 h# l$ R
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
9 v' a. `2 H0 s) J5 R$ e, fother values. The Squares of Odd numbers are all on this angle.
+ i% ]# {; ~* d5 x# t+ y9 t315-deg Angle = (Ring# * 2 +1)^2+ v. P# X/ v6 N7 f- |& D& X! Z
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441* A c: P+ Y3 d. g3 p+ V9 u) X
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
$ \& p( g- A" z; |5 Z371 This number is needed to calculate the angle that the 1st value of 390 is on.
' |% d3 P. @ C$ sAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
: x6 e' o- [- k% p$ YYou may have to occasionally adjust the Angle calculation because sometimes you will get a
2 B$ H6 J; g. U7 _2 d% Anegative value when you have a number that is approaching the 0-deg angle of the next ring.8 G- `5 \) J1 F4 J1 Y6 K
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
0 h. \; U. u! M% ~& w" L3 z370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
2 M2 J) |! W5 C) ?4 r371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this0 Y6 T! T- z9 M
would actually be 357.75-deg.' V ?6 u# f( h0 y |# @6 X! c
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.- l/ v7 I W) U
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
3 x% E( Y0 j: b; P! x6 X((Ring# / 45) * Angle)
* f. n- {4 M) |( cAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg* g0 H! E" P9 ~/ x% F
angle. If we want to know the value of the number that is 45-deg to this number, we would be% q. i! e z# z2 q
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
% `5 B3 u7 S! ^" g(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =- m8 @/ F" f; m* Q2 j% w( v# t
399.99 is 45-deg to 390.
- W- K+ [* f2 ]( F7 }Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
& M- o0 ?* |2 E2 W0 bto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract/ X: I1 C) [( ]2 G* i
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
9 k& V6 r2 p2 k1 R# v8 n( h# Tdeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
8 d2 `! J/ W& Y: D- ]; i: |) u5 Iwould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which8 E- O- K% V; G, n$ e5 f( r' ^+ _6 J3 ]
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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