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原帖由 yese 于 2011-1-10 21:21 发表 $ G% ~" H3 A9 M- w& @: J2 ^
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose* G3 V5 I/ u4 ]3 b
corners are connected, creating a cross within each box. Because there are fifty-two weeks
* {/ @+ k( K! C. j* kin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price$ \! h4 w! U7 \
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional" e8 W8 f; {# S0 Q$ u: u
divisions can be used and the angles within the original square of fifty-two still retained if3 Q6 v: K r9 \& ?: n) i1 {5 d
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
; ^' F! ]# I5 b$ ragainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still1 v7 a1 F, ^6 {7 D5 u9 o7 _
produce the same angled lines across the chart. When the internal corners are connected,
/ Y- R! y. v/ \2 J; _the grid produces both positive and negative true geometric angles of 45º. Therefore, a; ~4 U$ w: f0 c7 }1 ?( o% C e
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the, K2 n" ~7 Z" [+ M1 ]
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
( b$ T/ m5 ~- m. ^the Gann boxes in several ways, including further subdivision of the square by thirds or' o" m* L$ u" x: z
eighths. However, for this discussion we will not venture down that road. * r9 v$ }; Z: ]! z m/ q4 L- f
$ i0 C( r1 Q$ T" P# M5 Z4 n2 f2 n. Dem40.gif" border="0" smilieid="203" alt="委屈" /> |
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