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原帖由 yese 于 2011-1-10 21:21 发表 " {4 m" n( r0 \- ?4 ?9 u
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
) Y/ }5 k# z P! p( _& f) lcorners are connected, creating a cross within each box. Because there are fifty-two weeks
! e1 h" O/ P9 v5 z2 win a year, the weekly chart is using the square of fifty-two. But if you look closely at the price: P, r' Q3 o8 x
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional
$ z, r9 n1 s( Gdivisions can be used and the angles within the original square of fifty-two still retained if
# D3 c* q4 A% }7 q0 v3 `) f9 [only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52, ]& Q+ d1 m. ~5 V d# ~
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still- v$ J$ |. }3 B* n- K& b
produce the same angled lines across the chart. When the internal corners are connected,/ \' {7 t: J& g* S1 T
the grid produces both positive and negative true geometric angles of 45º. Therefore, a
4 M; G! f/ |4 T% g }- t% {simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
5 v) W- a7 I& J- e* ~1 r, S4 D" G0 xboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
% b5 @1 U3 ?* zthe Gann boxes in several ways, including further subdivision of the square by thirds or' A! F, s+ I. F
eighths. However, for this discussion we will not venture down that road.
/ ^! R/ U' N+ A; J' X( A: p/ K. p, ^& \4 j6 v+ m9 T6 F; ~
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