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原帖由 yese 于 2011-1-10 21:21 发表 - r, g; Y- Y1 ?1 h9 V
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose; \# e0 M: d$ t3 `7 T/ h- o I5 T2 k
corners are connected, creating a cross within each box. Because there are fifty-two weeks+ l! I% u/ g9 I- R4 U1 ^2 J0 l0 E1 Y* \1 F
in a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
. f$ v( q. j" D- xscale, it is clear that one box does not cover a price range of $52. Multiples or proportional
- v% A: C" U2 y8 P! c) K8 b, s) Kdivisions can be used and the angles within the original square of fifty-two still retained if
) A+ p8 w% P# h* ` |8 W6 R: xonly a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
) M: z$ y7 T' D( u6 oagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still
! r+ }: h$ G" u% l) Lproduce the same angled lines across the chart. When the internal corners are connected," b4 c9 O) O0 Q) h2 o2 ?* G# b
the grid produces both positive and negative true geometric angles of 45º. Therefore, a0 T, Z; F3 j' ?" y9 ?) t, b
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
7 l7 S- [0 I; w+ a, Kboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
0 t$ ?" o4 {$ S: n( x% X" N5 I3 Athe Gann boxes in several ways, including further subdivision of the square by thirds or- ~' x( C9 {* `/ {0 D
eighths. However, for this discussion we will not venture down that road. * i D% {+ T5 |1 n* H2 S- M
Z+ T- q$ f, @
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