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原帖由 yese 于 2011-1-10 21:21 发表 ![]()
+ {3 d" k& A, fBut there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
; Q0 ]3 G4 Q; E2 k( I& Bcorners are connected, creating a cross within each box. Because there are fifty-two weeks
9 j# x- Z4 u( O7 {9 {; }1 Y6 U0 zin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
: f. R6 ]& S. d& ~0 C1 v' Bscale, it is clear that one box does not cover a price range of $52. Multiples or proportional
9 E- K* T* Q8 x) e2 tdivisions can be used and the angles within the original square of fifty-two still retained if
+ ?7 r* O8 T/ X; U4 U& Donly a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
, N# d8 M- n1 I3 [+ C6 @7 e! Gagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still5 Y' y# y1 P1 c) P1 r, l# t7 {1 W
produce the same angled lines across the chart. When the internal corners are connected,+ _) B! N1 ^1 p4 v4 t
the grid produces both positive and negative true geometric angles of 45º. Therefore, a
% u8 o5 P; H) t# V' x& v& |simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the9 L1 J8 t# g& I3 [
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
$ |" T- W/ E3 K: dthe Gann boxes in several ways, including further subdivision of the square by thirds or' J5 c* q( `; \. N1 a) c
eighths. However, for this discussion we will not venture down that road.
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" x) C a" y- g S# ^1 d* mem40.gif" border="0" smilieid="203" alt="委屈" /> |
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