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谁翻译一下,谢谢哦

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1#
发表于 2011-1-10 21:21:29 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
" `2 I1 ~5 W* }- R3 ]& _, ]' Rcorners are connected, creating a cross within each box. Because there are fifty-two weeks
5 e* N0 q+ d: sin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
0 k* I* ]! ~: q% ascale, it is clear that one box does not cover a price range of $52. Multiples or proportional
% ]) v, y# Q) J6 Ydivisions can be used and the angles within the original square of fifty-two still retained if- `: [' @3 I# c
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $522 X( b$ `2 t. g2 j; _6 a9 Y5 H
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still* E+ A5 B5 K* i2 ~; ^
produce the same angled lines across the chart. When the internal corners are connected,
+ U, e8 k9 a' M- x6 Bthe grid produces both positive and negative true geometric angles of 45º. Therefore, a
1 a) \- h. V7 G( x% Q. Isimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the
( u: W- D" E6 q2 ?/ m1 U& o6 [$ Fboxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by. D7 G2 @5 X2 }! j7 @
the Gann boxes in several ways, including further subdivision of the square by thirds or
6 f: h. d% m9 g/ q1 E! ^# M4 r7 h) reighths. However, for this discussion we will not venture down that road.
2#
发表于 2011-1-10 21:40:36 | 只看该作者
原帖由 yese 于 2011-1-10 21:21 发表
+ {3 d" k& A, fBut there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
; Q0 ]3 G4 Q; E2 k( I& Bcorners are connected, creating a cross within each box. Because there are fifty-two weeks
9 j# x- Z4 u( O7 {9 {; }1 Y6 U0 zin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
: f. R6 ]& S. d& ~0 C1 v' Bscale, it is clear that one box does not cover a price range of $52. Multiples or proportional
9 E- K* T* Q8 x) e2 tdivisions can be used and the angles within the original square of fifty-two still retained if
+ ?7 r* O8 T/ X; U4 U& Donly a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
, N# d8 M- n1 I3 [+ C6 @7 e! Gagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still5 Y' y# y1 P1 c) P1 r, l# t7 {1 W
produce the same angled lines across the chart. When the internal corners are connected,+ _) B! N1 ^1 p4 v4 t
the grid produces both positive and negative true geometric angles of 45º. Therefore, a
% u8 o5 P; H) t# V' x& v& |simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the9 L1 J8 t# g& I3 [
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
$ |" T- W/ E3 K: dthe Gann boxes in several ways, including further subdivision of the square by thirds or' J5 c* q( `; \. N1 a) c
eighths. However, for this discussion we will not venture down that road.

- L+ M0 \# t0 }  h4 l
" x) C  a" y- g  S# ^1 d* mem40.gif" border="0" smilieid="203" alt="委屈" />

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3#
发表于 2011-1-11 10:11:55 | 只看该作者
  但有一种方法来解决这个问题。图5.12显示一个系列的盒子; h1 X% W4 |- B$ B
  角落是相连的,创建一个交叉在每个箱子。因为有52周
% a3 u  B) C/ g; s( E3 h! k, K  一年内,周表是使用广场的名。但是如果你审视其价格/ C8 ]; ^! a% h/ U, w: s
  规模,但可以肯定的是,一个盒子不包括价格范围52美元。倍数或比例
! r8 D! O/ X( M5 L0 I  部门能被使用并盎格鲁在原广场仍保有52例' y; u) l. \  ]& q; p  o
  只有一个箱子里展示映射f

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