|
|
原帖由 yese 于 2011-1-10 21:21 发表 8 A" F& Y1 h! c4 n: {
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose$ d: X1 Z7 P. c: m7 x: _
corners are connected, creating a cross within each box. Because there are fifty-two weeks
/ q9 G# T& _/ t/ j3 w9 K2 Yin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price
# Z8 A) @( j9 w- Q& F& vscale, it is clear that one box does not cover a price range of $52. Multiples or proportional
C- x K8 z+ V! jdivisions can be used and the angles within the original square of fifty-two still retained if
7 ?, V/ _2 ^6 Z" d: Ionly a single box were displayed mapping fifty-two weeks along the horizontal, versus $52; T9 l4 k1 {( Z. t3 P1 d: |
against the vertical. Although one large box is not useful, four boxes and sixteen boxes still
& _- L9 b. z' H3 ]produce the same angled lines across the chart. When the internal corners are connected,
, g% e K9 q8 u& m* ethe grid produces both positive and negative true geometric angles of 45º. Therefore, a. X) G4 ]/ d, d* V4 x
simple solution is to draw the Gann boxes, establish a true 45º line, and then remove the' i; ~" F1 _+ j( j: Q5 M
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
5 A$ [' K+ R6 _( x$ `3 Tthe Gann boxes in several ways, including further subdivision of the square by thirds or
7 V: z# I. b: H% P$ |; Y, Jeighths. However, for this discussion we will not venture down that road.
' Y! _& z. X) G9 ^: s) N% Q0 ^8 g a! B
em40.gif" border="0" smilieid="203" alt="委屈" /> |
评分
-
1
查看全部评分
-
|