|
|
原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
4 S5 Y" n5 `* ^9方图计算公式
7 [* s2 J8 V3 e3 N在下面几个角度线上的:# \1 L, d4 }- E S- V7 F
0 degrees: (2n + 5/4)squared
2 N9 K+ b( p4 Z' G, Y: Z45 degrees: (2n + 6/4)squared
0 `6 J" E* h; B5 a2 v: A90 degrees: (2n + 7/4)squared
" N9 b; U. r8 L' o; z. |135 degrees: (2n) squared
9 g' F$ Y1 b3 @0 \180 degrees: (2n + 1/4)squared" w: t; H- _2 j" ]- v
225 d ... $ W( i! t; y! b( Z
6 D9 p% k. H5 T+ ^1 G8 E& A/ x+ |+ B
% C d" Q% ]3 U, J& J. P) h! d$ P
是这个吗?5 ~, g' K6 @2 {; L, d' q
& s8 a% M/ }. N* u2 O! S/ _ V% r# U2 W( `
Square of Nine Essentials
6 J% Z* {4 d, R1 |! {7 P9 M( e5 aDaniel Ferrera, 2002% }" H& O9 I$ B, p# ~ t
In my experience with working with this method, price & must balance on a hard aspect.
6 s+ x% K2 x5 lThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
. Y9 b3 |4 ^6 l: x6 Pimportant being the squares or 90-deg harmonics (0, 90, 180, 270).
$ |' w$ V+ X# |2 mIn terms of selecting a past date and price to start from, I have found that the lowest low over
2 c6 N ~7 Q: w) g- zthe past 365-days and the highest high over the past 365-days have the greatest influence on
% |( `# o- P- L& n- B+ Lthese balance points. This technique can be used to generate the horizontal support &
: K K' O! y) g8 Jresistance levels for intraday trading. This is extremely useful when you anticipate that a
g4 @8 B" B8 Z4 c0 uparticular day will be a trend change as the result of cycles or counts, etc.
) K7 X$ N# M% d8 [/ g3 L$ \3 HCarl Futia's formula for this reads
B* K! F4 Q" E& g: ^1 [=MOD 360 ((price distance or Time change)^0.5*180-225)0 w, a8 V5 A6 n3 a$ J
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the O6 `7 K' ~. B/ X9 A# s4 W
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
5 p% F7 |/ l0 f2 e1 J8 gof Nine chart.
1 B* M( _' L8 k8 S$ PIf you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
0 F+ o+ I: h9 O& x/ A7 obut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
, C- J" d8 q8 f. O" rexample, on the actual Square of Nine6 b5 T: l% I, E' {3 d; t
16 is on the 112.50-deg angle,' X) |* `" C% [ u: `: H, G9 f$ V
36 is on the 120-deg angle,; K( C* R& m, a, |! [
64 is on the 123.75-deg angle,
* j7 x2 J+ c8 G9 K2 K' d3 p100 is on the 126-deg angle and6 ]( Q! u) D4 R7 [, P
144 is on the 127.50-deg angle
2 R3 R# u$ Z; P% `3 {" Rand so on.
# o, t' R' D5 UStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
5 J0 J& e$ n% i; E' P* U J. V- wand the Squares of Odd numbers will Float.$ E) G+ c/ R" {0 V
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw5 J, Q7 m5 H2 ?7 |2 Z) W
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to" A& r$ _4 q" `' H, A% C: E& {- ^
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the8 k3 F% T+ R9 e; Q4 Z7 ?1 D
following formulas will be of great use to your research:: s% x6 x* y" X9 s; _( t
Ring# = Round(((SQRT(Price)-0.22 / 2),0)* |; [' X3 ]" X/ H; a% j: Z ]
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
, L% n& m$ B8 j7 fExample: The number 390 is in Ring #10 if you crunch the above formula.
- i: r7 c0 A0 ~2 F315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all* G, y( A( B( {7 u% v
other values. The Squares of Odd numbers are all on this angle.2 S$ S+ t5 s4 L/ l! b7 ]
315-deg Angle = (Ring# * 2 +1)^2) P! b( M7 ]0 n9 n& s
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 4418 \+ y: A& H) l/ k H- O3 W8 R
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
. J c2 J- C. B, Q371 This number is needed to calculate the angle that the 1st value of 390 is on.# @+ P( B3 P5 e5 p2 D
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
" W3 D) b8 E" KYou may have to occasionally adjust the Angle calculation because sometimes you will get a# Z' ?6 I, i3 S2 k1 D! ~
negative value when you have a number that is approaching the 0-deg angle of the next ring.
) l' |& l% e0 w$ ^For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
s O2 b- m! G$ x370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -# ?+ i- I( v4 q8 j
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this) K, u; M5 b3 ?7 M2 B( B
would actually be 357.75-deg.( L# _8 V0 ^0 c7 q' n6 A4 ^
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
, ?* j% E$ P2 Y* g/ ]To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +: a' [ s( q1 p
((Ring# / 45) * Angle)
( @! C7 K0 a7 O9 Y) l9 ]Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg) ]9 x; Z; `3 F# Q* Q" s* Y
angle. If we want to know the value of the number that is 45-deg to this number, we would be/ }1 n% O+ g) {) ]- f) G1 _
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:, l! G. e7 H6 v& d6 n
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
- _9 r% P% \4 d# L/ A% Y9 H/ A4 M399.99 is 45-deg to 390.
; }: @5 x( Q% e _1 |Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
+ Q. _4 C- d% L. }& Q: vto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract! y @. q3 V1 U2 A$ X( @# U
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
, k; \1 I7 w4 r& |( R% U: ^# Ddeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
: ?- o5 e: p7 s3 {would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which- X2 Y4 a& H/ X
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
|