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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
/ m6 C5 x: i0 S* J9 y7 z9方图计算公式, C8 J4 p' X0 G2 L3 n
在下面几个角度线上的:
2 i( ^% k$ [3 c% t0 degrees: (2n + 5/4)squared- W$ p) U& ]# f$ y4 A
45 degrees: (2n + 6/4)squared
/ V* j+ N9 t1 `4 l90 degrees: (2n + 7/4)squared
/ x8 r. V- k( }135 degrees: (2n) squared
7 w' Y0 p @' K4 g' R180 degrees: (2n + 1/4)squared9 @4 q z8 z$ D W" c- V
225 d ...
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是这个吗?/ N6 }" u# u# o2 q5 d5 j, K
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Square of Nine Essentials* R/ r8 J6 Z8 h: r
Daniel Ferrera, 2002
( e( p8 `9 t. F' Q! J6 f0 DIn my experience with working with this method, price & must balance on a hard aspect.) l" _' @( R3 Z$ q3 [2 n
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most7 W; C* w V0 @ u% ^! u
important being the squares or 90-deg harmonics (0, 90, 180, 270).9 S: {8 i5 p/ _% l
In terms of selecting a past date and price to start from, I have found that the lowest low over
4 s- P$ q. ^, xthe past 365-days and the highest high over the past 365-days have the greatest influence on
8 x& @. R: D' P4 _% |these balance points. This technique can be used to generate the horizontal support &
9 M" V9 E" [- [$ Z2 F2 G3 Z6 Xresistance levels for intraday trading. This is extremely useful when you anticipate that a; i+ [& w# Q0 M" U( Y2 z
particular day will be a trend change as the result of cycles or counts, etc.9 U& G) @" a: O/ I+ n
Carl Futia's formula for this reads
` U+ @3 l# M4 O" o=MOD 360 ((price distance or Time change)^0.5*180-225)
0 t" g6 J/ ~; Z* E) D5 p" y5 ~This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the' I6 x# D+ a" I3 c: a4 W
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
5 D( T0 b2 a2 G8 l* u/ `of Nine chart.. C. V' O& S+ ]( C# g+ o) R6 {
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
7 G; j! D0 q* R: v: Ybut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For, E5 o' g$ L$ g$ A; d& z
example, on the actual Square of Nine
9 z3 H( A7 Y L' I" p6 |16 is on the 112.50-deg angle,
y" U% q6 {0 \% q }36 is on the 120-deg angle,/ l) f( {- I i0 }$ d
64 is on the 123.75-deg angle,+ X, L" U9 F6 x9 s+ ? J' @! n
100 is on the 126-deg angle and2 O& b& z8 W" ~" n% ^
144 is on the 127.50-deg angle
; s% `6 }/ ? Y% t, i7 b# M+ k% _and so on.
* D1 q! L- V; TStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
+ a8 c3 o3 s0 f6 A& V' A% i( M( jand the Squares of Odd numbers will Float.0 m0 J8 l3 ^7 Q3 K' Y9 K
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
. b: o6 @3 L/ i2 @2 d/ s$ Tor actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
6 f2 m' y) j/ a- Y9 Uwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the. C6 \6 H1 q M6 o! @# w( v4 a8 Y) K% T
following formulas will be of great use to your research:
- o- f6 c) M, h( r4 J( S+ URing# = Round(((SQRT(Price)-0.22 / 2),0), h: [ Y: i' Y8 [
{This rounds to the nearest whole number, i.e. it eliminates the decimals}- o5 d3 v' e' T! |0 Q7 g
Example: The number 390 is in Ring #10 if you crunch the above formula./ {! Q8 I2 E; p: O1 e# h. Q- G
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all3 C- p; T c1 M; a) g) z9 n" m' J2 y
other values. The Squares of Odd numbers are all on this angle.
4 f% e- x L/ [! C9 F: `9 a" T* x1 Y315-deg Angle = (Ring# * 2 +1)^2
" l6 f" Q/ d2 p$ C0 _ g' tExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441" o3 h& f3 c4 y, K7 [
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
& S7 G4 P" T+ n2 U" w9 Q+ \6 l371 This number is needed to calculate the angle that the 1st value of 390 is on.
( \1 R* h4 p. a0 F" w4 @Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
7 M% I! i8 ^( W" sYou may have to occasionally adjust the Angle calculation because sometimes you will get a# J- e" Z {0 r4 d9 P: t* |- _
negative value when you have a number that is approaching the 0-deg angle of the next ring.4 j0 y) U3 ? n8 S# ^% w- {2 E
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number. t& u2 t% f1 V, _* [
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -8 g" z5 D) n6 O, D! D: x
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this- N0 e( N/ _9 k5 l$ u" S
would actually be 357.75-deg.
# K! n; w! y0 k0 uA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
& _' A# o3 Y, `% i gTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +8 n0 \# l1 U/ k+ a+ @
((Ring# / 45) * Angle), s: t7 b* |5 q0 z5 M3 A
Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg
& ^1 X: H* v; b9 Jangle. If we want to know the value of the number that is 45-deg to this number, we would be6 y! G M+ ?0 ]" H" l( S
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
. p) r( B5 j0 D( W- N8 D5 R' a2 r(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
8 @1 V: _0 N5 m" k0 H$ f: }: Q4 @$ q399.99 is 45-deg to 390.
0 M+ c8 `7 f0 N* k6 o& \& {Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg); _- e" M9 I. y, }/ H& m* ^
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
! P' D& @% |! [( K8 B90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
% f2 ~' G9 I5 \* Z B1 q+ ^6 ddeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we J6 C0 y2 Z- D+ e# k
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
& F* m- Z- S. t8 U$ W: Gis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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