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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
; k8 U* M' G. L0 ?0 M( [9方图计算公式
9 b6 x3 e+ ?0 X; q' m8 n& I' Q在下面几个角度线上的：
. G8 w1 E' f; k6 |' N! k0 degrees: (2n + 5/4)squared, f5 j+ l+ w( Z: L$ Q
45 degrees: (2n + 6/4)squared" x( M [$ \ f( q1 D4 g
90 degrees: (2n + 7/4)squared
* A7 H; j& _# M6 d5 j135 degrees: (2n) squared
! R e( R$ X1 \' T# P: F" J! ^180 degrees: (2n + 1/4)squared7 V/ w6 M8 R3 [7 j
225 d ...
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* j+ L" v( O- r! x4 \9 B% Q2 R' U4 y5 |% F' U: K1 _1 h0 O6 J
是这个吗?* ?- U9 [" c8 _7 [; |" d2 n
4 v ?( V$ y1 X/ j) |, t4 S( m) E! I P z% E
Square of Nine Essentials) b+ |# Q' A* o: d8 g
Daniel Ferrera, 2002
$ E& j( T" v; z l: k6 ]In my experience with working with this method, price &  must balance on a hard aspect.. ?* Z9 Y/ w- R4 j7 C j
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most! T \ L* x; ~7 l7 o
important being the squares or 90-deg harmonics (0, 90, 180, 270).# V5 o( t$ h% K; `5 d5 t
In terms of selecting a past date and price to start from, I have found that the lowest low over
M, q* U7 _) m: }) _' Y/ h& cthe past 365-days and the highest high over the past 365-days have the greatest influence on* _. |) {; r- }" O
these balance points. This technique can be used to generate the horizontal support &
6 [7 J' L, F" e; U4 Eresistance levels for intraday trading. This is extremely useful when you anticipate that a0 B7 i+ X! \5 C/ \3 b
particular day will be a trend change as the result of cycles or counts, etc.! T# ?; x1 t8 n4 X
Carl Futia's formula for this reads% L1 ] c1 E$ C$ y8 d; k6 u/ E
=MOD 360 ((price distance or Time change)^0.5*180-225)
% R, V5 ~6 {6 ]This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
) Q# x K% C6 G' gSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
' \+ E) v" L) X: M. P+ wof Nine chart.6 d9 ]2 j; l2 p- n
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,6 w' Q* D% U) k- o; N
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
" n j) D, {8 M- G; \2 Y( }example, on the actual Square of Nine
- `2 T# F8 H9 h7 e; N/ T0 m; F16 is on the 112.50-deg angle,) W; H8 C: |, t8 | G! S
36 is on the 120-deg angle,
( K9 \. H+ H9 E$ g; D: P64 is on the 123.75-deg angle,
/ C' k1 d6 `% E5 A: a& ]1 Y100 is on the 126-deg angle and
: { Y' q/ t. t8 ^# x: k144 is on the 127.50-deg angle
+ x9 u$ N6 p1 j6 e( Hand so on.
9 R6 O6 O% x" N4 G2 ~Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle2 A; s( N4 [1 |7 M' P' s
and the Squares of Odd numbers will Float.$ Q( w8 }- _$ G& p4 S C
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw' T" k1 U7 u9 r( G3 Z. g
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
4 |' H9 t. s* u9 ?, I# l# m8 G$ \" uwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the! I% a g7 L8 ^, U% E, b6 v
following formulas will be of great use to your research:' y6 ^/ o+ b# w$ w* i0 f, L( g
Ring# = Round(((SQRT(Price)-0.22 / 2),0)
8 P& u1 w9 }7 H0 X{This rounds to the nearest whole number, i.e. it eliminates the decimals}
$ \* o" {/ f6 QExample: The number 390 is in Ring #10 if you crunch the above formula.
# {( F) L9 i9 s/ M( U315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all* f, p7 j. t9 y o8 {/ h1 c8 N
other values. The Squares of Odd numbers are all on this angle.
' H& U/ Y! @4 x6 n# e4 a/ D315-deg Angle = (Ring# * 2 +1)^2. t1 I& {4 o* k' g/ x$ `1 Z j4 u
Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441; I4 ]0 }9 T8 n& D. F. N9 H6 c
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
/ x/ q& ^. a* r4 ]& n" {371 This number is needed to calculate the angle that the 1st value of 390 is on.8 f2 N' v% b- f/ ]
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
& @- j, K; d3 p; S5 _% FYou may have to occasionally adjust the Angle calculation because sometimes you will get a
3 I: d) ^8 B/ m2 Q5 r4 i: Gnegative value when you have a number that is approaching the 0-deg angle of the next ring.
' [5 e( u, @5 B& v% o/ Y! XFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number3 e9 a0 W0 i% o- v* ?
370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
. k6 b) I6 y, u9 y+ C* R; S371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
5 S9 ~- I9 Z- y1 S6 D9 Dwould actually be 357.75-deg.
: i4 Z; s; u, o0 MA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.% m5 s* v$ P( \5 H
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +$ F% {4 e2 Z2 M0 |8 u
((Ring# / 45) * Angle)1 f5 s+ L: r. n4 }- \2 [! x( W
Angle is this formual is your input value. For example, we know that 390 is on the 85.50-deg
2 X; U$ ^0 J4 |2 x7 J( kangle. If we want to know the value of the number that is 45-deg to this number, we would be
1 b; _, H( J( ]% e6 d0 U! Y# E' j2 uinterested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
1 _' B! G" u( I0 b* s' Z* F(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
# _ {: k5 S4 ?3 u, W; J399.99 is 45-deg to 390., H" }: W1 V/ I5 m) d9 }+ R/ ~# ~
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
2 F' N r8 Q9 @2 N6 _to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract- P1 }, Q: s( L6 I% m0 H# m; M
90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-, }, J" Q. |" S, V% R' M( h
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we- e! d) F C2 ~% K
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
3 ?0 M: t; k9 E& _; m k2 Dis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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