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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
* P; ^0 k& V- }1 W: W, ~# j7 Z9方图计算公式' H5 V1 n& Z2 s' a+ H2 F
在下面几个角度线上的：* c$ E7 Z+ j. b& r) W
0 degrees: (2n + 5/4)squared
& c: L: i1 T2 z+ W6 m$ U45 degrees: (2n + 6/4)squared
7 L; ^9 g$ [2 `' O; d" A% |6 [4 M90 degrees: (2n + 7/4)squared# n5 o# Y4 S; a, A& s
135 degrees: (2n) squared
- @1 K) N' H9 G180 degrees: (2n + 1/4)squared! ^3 t" `# H! Q- J% L6 s
225 d ...
1 \; ?1 I4 o' z3 F6 U! ]& N+ |3 @) ]- y' E _4 ?; c
: B; a7 N! r2 V: g8 L. S/ q
是这个吗?3 b8 L( Q9 U9 p6 [" T
* d0 S9 [1 E5 w$ A1 D$ R" e' a( x6 E# } H( A3 T" \* I
Square of Nine Essentials
9 p9 h4 D- x+ g& {- ADaniel Ferrera, 2002
9 R. z& d2 l h# q! f5 s6 p. HIn my experience with working with this method, price &  must balance on a hard aspect.* ]/ w" N5 b; k+ x5 n1 N
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
, I/ K z" x- W( \$ j5 }0 Timportant being the squares or 90-deg harmonics (0, 90, 180, 270).
6 [4 X+ A' R( U' P4 |In terms of selecting a past date and price to start from, I have found that the lowest low over+ H# `/ N( c H& j u* N& V% n
the past 365-days and the highest high over the past 365-days have the greatest influence on$ T7 G. z4 c: S0 c1 P
these balance points. This technique can be used to generate the horizontal support &' M5 R9 l/ f$ ], _) I9 L3 k& b
resistance levels for intraday trading. This is extremely useful when you anticipate that a3 I! n6 p' N5 O$ Q; K
particular day will be a trend change as the result of cycles or counts, etc.% K9 X2 b1 Z" ^6 f" i3 c. z- f3 J
Carl Futia's formula for this reads
* f- ?. `/ m" Y1 p: h=MOD 360 ((price distance or Time change)^0.5*180-225)
: y' K' C0 ^ w6 Y: [2 s! cThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
- V- S& V1 c' z0 TSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
5 {+ F2 j( ?3 p2 F, [. N5 dof Nine chart.8 y% }1 a8 [% {; G+ u$ @
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
4 s9 @' S2 C: c8 o% \7 u. gbut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
/ F. D: q( x5 M4 n) e4 fexample, on the actual Square of Nine
1 R5 y2 C& _8 b' @6 d16 is on the 112.50-deg angle,8 G7 \; k0 v5 m. n$ Z
36 is on the 120-deg angle,; W6 G( u2 G j0 T, L
64 is on the 123.75-deg angle,
" i$ i/ H4 @5 s3 P100 is on the 126-deg angle and
! q+ q: U0 [* T, o9 L4 { r) g144 is on the 127.50-deg angle
5 |% g; y- J4 k' i" Tand so on.& n, s' L- G, _8 S3 w1 h1 W
Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle/ P5 F0 P4 Z6 p3 Q0 \ E
and the Squares of Odd numbers will Float.
1 x% l3 U T2 S7 n% k- W- P2 R# B+ oCould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
+ |8 c" q0 k- W8 i! L/ f+ lor actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to- _% `! e, v0 z& ?8 j
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the
! ^1 n" M1 i( S! R. W: ~0 J: Dfollowing formulas will be of great use to your research:
: S. F* O7 [, \3 y" gRing# = Round(((SQRT(Price)-0.22 / 2),0)
% b. T) i: v7 C$ p: s+ S{This rounds to the nearest whole number, i.e. it eliminates the decimals}1 T p$ W$ h; H# H! X4 {; q0 j/ n9 p
Example: The number 390 is in Ring #10 if you crunch the above formula.4 N T: u% v+ d- t1 q
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
8 Y9 x+ O5 x Lother values. The Squares of Odd numbers are all on this angle.! F! |- p. t( D% J/ |
315-deg Angle = (Ring# * 2 +1)^2
) e" U) i$ X/ S+ ^3 sExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
7 u0 r( N( _7 i6 uThe Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =# B# M) x ]* ~' ]$ W
371 This number is needed to calculate the angle that the 1st value of 390 is on.
' q6 Z' a" x3 l4 n8 Q2 }Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
7 K( J3 R2 J7 |% hYou may have to occasionally adjust the Angle calculation because sometimes you will get a1 q& }" G( p+ C) `( e2 j
negative value when you have a number that is approaching the 0-deg angle of the next ring.! e% O9 @8 _+ Q. F( t0 m
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
2 Y5 y- l5 r% z& m( }370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
9 b4 P: W8 z+ m& y u) A: h) S* ^371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this1 W3 F7 U- g9 S+ X0 X
would actually be 357.75-deg.3 }' b/ J% p/ \5 p
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.% X/ T- D/ S, J1 X" Q: j
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
* C9 m2 z& h# c( C7 E- A( V((Ring# / 45) * Angle)
3 ?: k0 x" x0 }+ i5 @* k& n9 jAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg
/ ~8 s1 W5 Y5 Eangle. If we want to know the value of the number that is 45-deg to this number, we would be
3 t2 l0 U/ J$ V% z; j: yinterested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:- y# s! c8 O$ L6 H. d
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
4 r; ~0 k" b3 S4 b( K' S399.99 is 45-deg to 390.
! S( L. ]" W% z" JKeep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
2 l1 M$ V; g8 Mto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
9 I1 E+ U( ^4 a7 v6 |: l# h90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
$ u/ I. z- o# P" `/ W5 Ndeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
/ ~) {2 `& C7 g) }0 rwould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
2 u- j+ m& h6 @& z" n1 i" Kis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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