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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() " Z7 {, Y* P3 t$ X3 i8 H" Z8 i. p
9方图计算公式
4 _- c6 g6 d) X$ g. }5 H+ Y, s在下面几个角度线上的：
1 g# C3 R9 i/ G$ Q, I0 f0 degrees: (2n + 5/4)squared4 n- Y* r5 w1 W/ U
45 degrees: (2n + 6/4)squared+ Q) n+ I3 B9 p0 s' P% t4 c
90 degrees: (2n + 7/4)squared
/ w. H; J! e% k1 h$ k+ U- F135 degrees: (2n) squared
0 \+ l# a& J- I1 w180 degrees: (2n + 1/4)squared! C( Q/ c9 _) v( j
225 d ...
2 C- @7 {9 Z/ z' o1 s( I, T0 n" D% f; j
+ q9 e' ^' M( G4 ~3 w* C6 G
是这个吗?3 k# ?3 \: `3 ]4 s1 T/ C1 j+ Y
( {. M7 q7 D" {) Y
9 O' H5 e2 J1 E
Square of Nine Essentials1 j& d( B/ M6 K/ W
Daniel Ferrera, 2002
% m2 ?. X; T# a, rIn my experience with working with this method, price &  must balance on a hard aspect.4 ?' C8 I) G9 b* k! s3 w. T5 R5 Z
The hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
k- K1 ]8 O; U+ j0 U% g! H- \" timportant being the squares or 90-deg harmonics (0, 90, 180, 270).( ]: f) ?! F* I4 S- P8 V& `2 W
In terms of selecting a past date and price to start from, I have found that the lowest low over
- R% I. Y! m& }! {the past 365-days and the highest high over the past 365-days have the greatest influence on
0 B4 {; t3 J7 G- H8 mthese balance points. This technique can be used to generate the horizontal support &0 S- L5 L! U$ B
resistance levels for intraday trading. This is extremely useful when you anticipate that a
3 Z- e [9 c" D% y r, Oparticular day will be a trend change as the result of cycles or counts, etc.
4 Q p' r; w5 J* r1 n- ]9 SCarl Futia's formula for this reads
' L5 B- ]/ a, i0 v=MOD 360 ((price distance or Time change)^0.5*180-225)9 {. ?0 v: _: N$ o4 g) |2 v
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
0 `( t8 E: _- Q; L; sSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
. g. Z, U, d3 M9 O+ `8 V* }4 Cof Nine chart.0 ?6 x/ @; u+ L
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,
0 o7 j8 r* |& G8 S9 A# {" t4 Hbut the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For
! ^7 K6 z% r. _ w! l1 @, }. Dexample, on the actual Square of Nine
1 G: \* A9 M0 L( ~! h: x16 is on the 112.50-deg angle,
m5 N2 F. E% f0 x3 A6 L% s36 is on the 120-deg angle,0 e' G- \6 @, U t A" F' W
64 is on the 123.75-deg angle,, s% |- ^8 i. a
100 is on the 126-deg angle and2 e1 m. ? z5 K: a3 c" \
144 is on the 127.50-deg angle
. H8 V: B. n7 u, S) Xand so on.
, p0 l& ? a# q- }Starting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
Z: H, @1 u3 m; d$ g/ s3 ?and the Squares of Odd numbers will Float./ d) W; r* O! T3 @ v. F( t0 w
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw
$ X3 w: H/ p0 }; d! @or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to% R+ C1 j% w. V2 v3 \5 k! v
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the
8 u6 [; c% p- `# Jfollowing formulas will be of great use to your research:
3 {3 J, K; G% {% ^1 _Ring# = Round(((SQRT(Price)-0.22 / 2),0)
! l+ s2 O/ ?) r0 F" q- a4 d5 e7 h{This rounds to the nearest whole number, i.e. it eliminates the decimals}
0 q4 o. z0 R# m1 d" z* GExample: The number 390 is in Ring #10 if you crunch the above formula.
, y: T: }# @) s) P9 @/ G5 E$ B315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all4 f# n7 E: K8 T9 u- J i
other values. The Squares of Odd numbers are all on this angle.( V5 u6 z7 Q7 q* z
315-deg Angle = (Ring# * 2 +1)^2
$ ^$ b5 B. j& V; \Example: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441
- G6 O8 [% c1 K' l+ A: ?( `The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =" j' o3 c/ V3 X( c$ G1 \7 b
371 This number is needed to calculate the angle that the 1st value of 390 is on.
7 D( M- |8 g; t8 T& [/ _8 OAngle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
7 j5 i- G; C, D! c' L8 DYou may have to occasionally adjust the Angle calculation because sometimes you will get a0 t0 F0 V% W( _9 @# U. Y; R# ~
negative value when you have a number that is approaching the 0-deg angle of the next ring.
0 m/ O r1 p7 O; r6 yFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number
' u9 t4 m$ \* J# R8 U370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -" q. C/ e# i. h+ F4 g# c5 N6 X" G
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
( q2 c. w4 d/ D: s3 qwould actually be 357.75-deg.. ~; f5 c, Y, r4 y
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.
7 Y H: B! ]: h+ pTo generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +# Z. T2 O" N+ Q3 R0 F+ a9 M. ~
((Ring# / 45) * Angle)
2 M" P7 ^6 o B7 {% J8 lAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg7 m8 X6 Y1 y6 J
angle. If we want to know the value of the number that is 45-deg to this number, we would be
5 ^% C8 C* X+ a; _5 Einterested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:
e! _' Q& I! e: L. w6 R(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
5 e0 U" k9 A$ I$ a( L' f: K399.99 is 45-deg to 390. b) d# F. x5 V- z+ F8 Q& d
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)
, z R. J2 U; I$ k$ Uto an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
0 C- P; D5 C$ B90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-3 y! ]8 j# p0 v! x, p
deg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
: p2 c1 r1 A6 y, ewould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which
1 \) c: z( x: K/ d7 v! Iis 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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