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原帖由 5575338 于 2008-7-31 17:48 发表 ![]() - v+ f* _+ D' q. a
9方图计算公式# H: j; T( i2 W" u. f d( F
在下面几个角度线上的：/ |3 F6 s& D5 a) Q5 v6 N
0 degrees: (2n + 5/4)squared
0 k7 n! T( i6 r1 x' O3 T45 degrees: (2n + 6/4)squared) U3 L( y$ L3 o: Q4 @
90 degrees: (2n + 7/4)squared2 K# Z% k! J8 z( a9 P0 c+ X
135 degrees: (2n) squared
/ q+ S" F1 _" S# X180 degrees: (2n + 1/4)squared
0 F6 S! b. C9 \0 A225 d ...
F0 D" M. w! f
$ c- y7 J+ b, J7 g
. p7 z1 G; b. w是这个吗?4 t. @( V# a; |! p
- s- g) l0 N- h: U' h- s
2 k5 |. g- w- w5 |Square of Nine Essentials% u a! X5 P9 T5 }0 ^) B; u% H/ ^
Daniel Ferrera, 20029 W- V0 p! ]7 ]6 i6 {
In my experience with working with this method, price &  must balance on a hard aspect.
- m. m+ y( }# k6 @1 K: f- A4 TThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most
: t4 E( w6 E! R; l# V' U! gimportant being the squares or 90-deg harmonics (0, 90, 180, 270).: k" Q0 ]* d+ C( S( d3 k5 D
In terms of selecting a past date and price to start from, I have found that the lowest low over
" Q9 W, T6 }8 Xthe past 365-days and the highest high over the past 365-days have the greatest influence on
0 {5 U ?3 X, n# T9 A* V. sthese balance points. This technique can be used to generate the horizontal support &2 U1 B' B/ I6 M4 n" {
resistance levels for intraday trading. This is extremely useful when you anticipate that a" r3 t' c- o0 H1 s" H1 i
particular day will be a trend change as the result of cycles or counts, etc.! ^: C( |; u h5 Z: U6 Y' L
Carl Futia's formula for this reads
* T# ~( M# W; [. G$ e8 f=MOD 360 ((price distance or Time change)^0.5*180-225)$ ~( [9 p) J! ]0 N3 D$ S
This formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the4 a/ Q* j6 Y! \3 }# q# j* m# v
Squares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square
4 z/ o! [4 Q; p9 i7 s% Jof Nine chart.% S! P8 q* W2 |1 v1 R$ X$ I
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,! B y$ e' ?# A# c) H( w" d$ G2 d/ Z- _
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For Q0 O: d8 e: C4 t: L
example, on the actual Square of Nine
+ h" i3 E1 w1 W# m16 is on the 112.50-deg angle,/ D: n* [8 u9 V3 \+ w
36 is on the 120-deg angle,
) \) F0 {1 r( m7 [, w# N64 is on the 123.75-deg angle,6 N8 K* O8 w2 L4 z# E
100 is on the 126-deg angle and
8 D. w% n6 U! l3 a144 is on the 127.50-deg angle
; c% t% P F8 Yand so on.
" X7 U# \4 G! U$ l1 |- k `! Z' n1 zStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle
# L4 z( a& \; q7 M' Iand the Squares of Odd numbers will Float.# A: F( R( [4 a) @4 S" y2 l, [6 E
Could this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw' L+ h* }. G+ v0 Y" A- c9 y( o7 f
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to
/ |0 N$ V) h$ m* l- E4 t# b2 U' Q* Pwork with calculations that are based on W.D. Gann's printed Square of Nine chart, the8 q1 y; A# O( F+ m9 ]/ w8 f' |$ @
following formulas will be of great use to your research:" d2 U* Z- Q' z4 t) _
Ring# = Round(((SQRT(Price)-0.22 / 2),0)
! U6 a$ z( B$ k( F7 `7 U) n5 x) ~4 W{This rounds to the nearest whole number, i.e. it eliminates the decimals}
0 ^- I3 @: ]' P3 T v7 rExample: The number 390 is in Ring #10 if you crunch the above formula. O$ F) J1 Z( r1 k! C2 h# B9 Q* R2 T
315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
! l8 q- ^7 ~$ b. m. z/ Uother values. The Squares of Odd numbers are all on this angle.; q* w( v$ K( C
315-deg Angle = (Ring# * 2 +1)^2
0 L% [+ W6 o2 B0 EExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441* W+ j6 A9 f9 v1 ~+ ?/ L L
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
3 @% s0 q7 R7 o$ r9 H371 This number is needed to calculate the angle that the 1st value of 390 is on.# f) D' A9 m4 s) v7 A$ [
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg; T; N- r2 u0 I" G: y5 w
You may have to occasionally adjust the Angle calculation because sometimes you will get a' W# }* f/ S1 U) r: r
negative value when you have a number that is approaching the 0-deg angle of the next ring.
9 L/ f. @9 Q5 \- f/ ~- q+ XFor example: We know that 371 is a zero-deg number. If you try to find the angle of the number
$ g: {% `$ ^. q/ l- l& t370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -4 _. i8 q; V W6 `" I
371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this% ^; ?% \0 k8 k) |; e9 D u; j0 Z9 W
would actually be 357.75-deg.
B* J% }* b9 |- aA simple formula to correct this is If Angle<0 then +360 else Angle = Angle.: k4 A6 }* G" L9 B" E0 a
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +) _0 r* B) H( K2 i1 E B0 G
((Ring# / 45) * Angle)
8 M N/ X, r9 _3 ~$ ?. w7 uAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg1 x, ^2 X% u/ X0 j
angle. If we want to know the value of the number that is 45-deg to this number, we would be- n; P$ C. y- g3 Q6 X
interested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:" ?0 X& g& I( T
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =
6 q9 [9 B9 Q# n399.99 is 45-deg to 390.
3 M" j9 }" M4 T& J8 }Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)! I" f5 m0 y9 [
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
# A% K" k `; X4 Y/ N90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
! y, \1 h% v$ H2 K8 t! V* R5 kdeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we
$ _( t: a: a8 Q k. T4 b; m( Owould have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which9 I- J7 Y% ]2 n$ r1 [' i A0 J: G
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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发表于 2008-7-31 17:48:41
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