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原帖由 5575338 于 2008-7-31 17:48 发表 ![]()
, v/ ^: V1 E# W- q9方图计算公式) f6 J7 X8 T# t8 A7 Q
在下面几个角度线上的：
- P* }6 ~( C1 n- R0 degrees: (2n + 5/4)squared
3 ]: m7 I! m4 q3 f5 y7 R45 degrees: (2n + 6/4)squared
/ \6 P! |. U ~2 \90 degrees: (2n + 7/4)squared
$ b- u& ]+ T6 `( Z135 degrees: (2n) squared2 I; M# Z' ]8 _" K: y* H: y) P" g
180 degrees: (2n + 1/4)squared
6 X* A( e) ~! [# S% u225 d ...
: R3 [# D$ a: a, j5 q9 C* E
9 O* z0 g1 C9 k( l" O7 A是这个吗?
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- k& A2 J- M; f, E e) Q) x' e, i3 i* n# ]
Square of Nine Essentials% A t( h3 Y, z; W
Daniel Ferrera, 2002% `# l. L: H0 f; u9 L4 m- S# w
In my experience with working with this method, price &  must balance on a hard aspect.
: ^& {2 }8 `6 x; w: t3 W% t" GThe hard aspects are 45, 90, 135, 180, 225, 270, 315 and 360 or 0 degrees. The most) ?5 G/ y* W; K8 k5 F) \4 ]
important being the squares or 90-deg harmonics (0, 90, 180, 270). C) I, E; ^( T3 y8 F$ r
In terms of selecting a past date and price to start from, I have found that the lowest low over
. t u' a r7 ?3 ~/ y' f. cthe past 365-days and the highest high over the past 365-days have the greatest influence on
, p7 L0 F3 {; Z% |1 athese balance points. This technique can be used to generate the horizontal support &
, {. l i7 Q* x8 F8 ?resistance levels for intraday trading. This is extremely useful when you anticipate that a; j- M' D. g: V' ^6 [/ n7 E
particular day will be a trend change as the result of cycles or counts, etc.8 }, [3 Z4 z6 ?( t; b; @) J7 o9 F' C
Carl Futia's formula for this reads
: X* j2 Q/ H/ T# P4 P, o=MOD 360 ((price distance or Time change)^0.5*180-225)
" z( F% t9 W0 o4 ?' DThis formula assumes that the Squares of Even numbers fall on the 135-deg angle and that the
; U3 b8 m# ]) N9 Y; p1 oSquares of Odd numbers fall on the 315-deg angle, which is not true on Gann's actual Square1 I; s+ s$ ]1 k/ a3 t% {
of Nine chart.* W. z' Q/ b9 ?! F
If you start with a "1" in the center, the Squares of Odd numbers will fall on the 315-deg angle,- B/ u' g; P% ? K
but the Even Squares (16, 36, 64, 100, 144....) will gradually float towards 135-degrees. For' v1 j+ W0 H7 s; i6 A3 T
example, on the actual Square of Nine
4 C# r3 X, Y( {# E& p3 }16 is on the 112.50-deg angle,) X/ \" [: C i' |/ j/ l# _
36 is on the 120-deg angle,
0 q P' V5 }& `* _2 M' H" F64 is on the 123.75-deg angle,
8 _) j& I) o. ?5 U; q6 c; `100 is on the 126-deg angle and8 |# z5 n! d( e" L
144 is on the 127.50-deg angle
0 t. v: `" g7 d" j K0 ~$ |0 ~and so on.
/ g: e6 ?( d+ FStarting with "0" in the center, the Squares of Even numbers will line up on the 135-deg angle. S8 O) z }2 G, |( Y% V
and the Squares of Odd numbers will Float.
. m! X7 ~# ]1 ~3 t7 vCould this amount of inaccuracy or "Lost Motion" be important? After all, it is impossible to draw3 c6 {3 ^7 d- o2 d* ]
or actually build a Square of Nine Chart based on the MOD 360 formula above. If you want to$ e/ z) d' x* j7 z9 x- s m
work with calculations that are based on W.D. Gann's printed Square of Nine chart, the. a" s! @8 s ]" h9 [2 Y# `& g
following formulas will be of great use to your research:
2 `0 `* }( k7 c- M0 ]9 URing# = Round(((SQRT(Price)-0.22 / 2),0)$ }( T7 Z1 \! J4 G
{This rounds to the nearest whole number, i.e. it eliminates the decimals}
5 A1 j2 G4 [1 f; a" \Example: The number 390 is in Ring #10 if you crunch the above formula.
" P H7 n+ h" X( ^" ?315-deg Angle: This is the most accurate angle of the entire chart and is used to calculate all
$ ^& e/ [% N9 E3 d+ r' X- L, \$ ?other values. The Squares of Odd numbers are all on this angle.
) C5 e1 a/ y5 T; V3 t8 F315-deg Angle = (Ring# * 2 +1)^2
) u- n2 k3 ]0 Z& ~/ QExample: 390 was in ring# 10 so the 315-deg number is (10 * 2+1) ^2 or simply (21)^2 = 441- O/ y7 o. A$ P* |4 t
The Zero Angle on this Ring = ((Ring# * 2 + 1)^2) - (7* ring#). So you would get 441 - 70 =
% Z: h( T: ~+ C5 c+ K5 j371 This number is needed to calculate the angle that the 1st value of 390 is on.' p2 f+ O: v* y9 o# H
Angle = Sum ((Price- Zero Angle) / (Ring/45)). So we have ((390 - 371) / (10/45) = 85.50-deg
% x5 c2 A5 l. \ N% \/ [0 f; a% C( gYou may have to occasionally adjust the Angle calculation because sometimes you will get a2 D$ K5 J8 }; {5 W1 K
negative value when you have a number that is approaching the 0-deg angle of the next ring.4 F3 W: i- z4 |9 c2 m3 p
For example: We know that 371 is a zero-deg number. If you try to find the angle of the number
" H& ?# g6 \7 b! Q; k8 Q o" r) p* p370.5, which is a number in the previous ring approaching the next ring, you get Sum ((370.5 -
5 n9 g8 L9 V& N4 e2 S371) / (10/45)) = -2.25-deg. If you get a negative number, just add 360 to correct it. So this
9 S: w1 X3 |: \" cwould actually be 357.75-deg.( }1 v+ k! e" `" @8 }" T9 H- `
A simple formula to correct this is If Angle<0 then +360 else Angle = Angle.# w! m% q2 O! ]7 M$ ?% B( y" W
To generate other values on the Square, use this formula: (Ring# * 2+1)^2) - (7* Ring#) +
! r3 b& [( H# f4 |# c( e/ P; @((Ring# / 45) * Angle)
, ?, O8 G2 W& Q% T5 h, JAngle is this formual is your input value. For example, we know that 390 is on the 85.50-deg- Z4 I. a+ P+ C+ h% Y' ~
angle. If we want to know the value of the number that is 45-deg to this number, we would be
. H h; A9 N& Einterested in the angle of 130.50-deg (85.5 + 45). Inputing this in the above formula gives us:4 \# @) B; x3 s4 t/ u. x7 y
(10 * 2+1)^2 - (7 * 10) + ((10 / 45) * 130.5). Simplified a little, we have 371 + (28.99971) =- w# n1 Z, y% g+ H; @
399.99 is 45-deg to 390.) N- M% I: m* p# Q! l& b, Y6 j* ?
Keep in mind that if you add or subtract an amount that will change the original angle (85.5-deg)* P& s! f5 d" n% v: F0 W& j
to an amount greater than 360 or less than 0, that you JUMP rings. For example, if you subtract
1 t2 G6 _0 [; ]" p90-deg from 85.5 to potentially find a square aspect, you get -4.5-deg. Add 360 gives 355.50-
- w" C0 H& P. i/ hdeg in the previous ring. We were using Ring# 10 in the formula, but for this calculation, we: \& Y/ f/ |) D! U, Y
would have to use Ring# 9. Similarly, if you added 315-deg to 85.5-deg, you get 400.50, which, q+ s; E5 f/ k" W
is 40.5-deg in the next ring. So you would have to use ring# 11 for this calculation |
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