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原帖由 yese 于 2011-1-10 21:21 发表 + ~( o' u3 q' f2 Z4 [7 G: O9 D
But there is a way to solve the problem. Figure 5.12 shows a series of boxes whose
. }5 W, W% v. j& r" ?1 J* E1 ^7 O2 ucorners are connected, creating a cross within each box. Because there are fifty-two weeks
$ `& u! `! H0 cin a year, the weekly chart is using the square of fifty-two. But if you look closely at the price7 G. ^% A, c5 Y& R- j, q
scale, it is clear that one box does not cover a price range of $52. Multiples or proportional
0 F/ |/ ]" I) V* t7 G0 pdivisions can be used and the angles within the original square of fifty-two still retained if$ G, d+ i q! q! B" r3 ?
only a single box were displayed mapping fifty-two weeks along the horizontal, versus $52
3 ?' m& j9 U' n+ K6 Iagainst the vertical. Although one large box is not useful, four boxes and sixteen boxes still# p' T* Q) S. g8 \) @
produce the same angled lines across the chart. When the internal corners are connected,
$ M& d: E) [( i9 J5 A# Y, J! \; W3 athe grid produces both positive and negative true geometric angles of 45º. Therefore, a
1 t, |8 g* o2 E0 isimple solution is to draw the Gann boxes, establish a true 45º line, and then remove the3 _; e4 U6 l5 n; v8 T! R
boxes. The outside frame of each box is a fixed cycle. Gann would use the cycle formed by
6 [! a4 ^! N0 {4 V5 D. ?8 _4 ~the Gann boxes in several ways, including further subdivision of the square by thirds or7 | m) ]' g) |: m6 Y3 j: y
eighths. However, for this discussion we will not venture down that road. ; r C' b8 O0 A4 G4 k8 s3 S* s
4 W4 W1 C k! V. ?em40.gif" border="0" smilieid="203" alt="委屈" /> |
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