原帖由 gubin1209 于 2008-11-29 08:19 发表 / Z+ I- n% }4 U7 T: I5 K+ F
请问GET怎么导入分时数据。。。 * q. ^2 e, }& m- r% s+ O6 c
把分时数据转成GET能识别的格式!
7 L3 @" {4 B5 C4 E6 M$ y7 I( V- _=========
[( R& E6 U B @1 O( R1/1/1970,5113.88,5149.53,5063.52,5145.62,188293570,1882935702 `4 [, _. G' E5 i4 p0 v
1/2/1970,5145.61,5154.86,5105.541,5108.12,108727779,108727779
/ i9 U' B$ |; _1/3/1970,5109.25,5109.25,5040.53,5040.53,140973540,140973540( c3 I: v- Q% d6 S: g. m* \1 Y
1/4/1970,5040.87,5063.89,4970.97,4984.16,218957179,218957179
. I0 W" O1 l0 c/ i3 i1/5/1970,4946.26,5008.36,4897.14,4981.18,165352328,165352328
" j2 M* J0 z J! ?& X0 K1/6/1970,4980.67,4990.97,4931.25,4939.66,95129122,95129122( b! [, n- ~! Z6 F6 l5 `0 _
1/7/1970,4940.65,5006.63,4940.65,4986.7,106686603,106686603
+ s* B# k/ a4 W# X9 ]- ^: H" d1/8/1970,4986.72,5034.23,4955.35,5032.13,142127822,142127822
. J$ H! |$ |; ?1 z5 R3 D' k1/9/1970,5102.53,5124.74,5045.69,5094.19,218468374,218468374& m3 V/ p& h) l5 s' C% r" u+ a, [
1/10/1970,5094.161,5099.451,5053.651,5062.98,110605768,1106057685 n# H) {( H+ R( _+ o; G
1/11/1970,5066.331,5078.681,5031.86,5031.86,102491368,102491368; b/ `" ^' H, L' {
1/12/1970,5032.99,5032.99,4952.96,4958.85,180523758,180523758
5 w4 N: Q+ {4 ?2 t8 H1/13/1970,4919.91,4946.76,4872.71,4930.95,160159928,1601599282 S; l) I% p: e, R/ _& C
==================== |